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Sholpan [36]
2 years ago
11

Point (6, 0) lies on the X-axis Oy-axis line y = x

Mathematics
2 answers:
tresset_1 [31]2 years ago
4 0

Answer:

x - axis

Step-by-step explanation:

Since, y-coordinate of point (6, 0) is zero.

Hence, it lies on x - axis.

tigry1 [53]2 years ago
4 0

Answer:

the answer is the y axis.

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((81x^3 y^(-1/3))^1/4)/(x^2 y)^1/4 simplify
malfutka [58]
\bf a^{\frac{{ n}}{{ m}}} \implies  \sqrt[{ m}]{a^{ n}} \qquad \qquad
\sqrt[{ m}]{a^{ n}}\implies a^{\frac{{ n}}{{ m}}}
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\left.\qquad \qquad \right.\textit{negative exponents}\\\\
a^{-{ n}} \implies \cfrac{1}{a^{ n}}
\qquad \qquad
\cfrac{1}{a^{ n}}\implies a^{-{ n}}
\qquad \qquad 
a^{{{  n}}}\implies \cfrac{1}{a^{-{{  n}}}}\\\\
-------------------------------\\\\

\bf \cfrac{\left( 81x^3y^{-\frac{1}{3}} \right)^{\frac{1}{4}}}{(x^2y)^{\frac{1}{4}}}\implies \cfrac{81^{\frac{1}{4}}x^{3\cdot {\frac{1}{4}}}y^{-\frac{1}{3}\cdot {\frac{1}{4}}}}{x^{2\cdot {\frac{1}{4}}}y^{\frac{1}{4}}}\implies
\cfrac{81^{\frac{1}{4}}x^{\frac{3}{4}}y^{-\frac{1}{12}}}{x^{\frac{2}{4}} y^{\frac{1}{4}}}

\bf \cfrac{81^{\frac{1}{4}}x^{\frac{3}{4}}x^{-\frac{2}{4}}}{ y^{\frac{1}{4}}y^{\frac{1}{12}}}\implies \cfrac{(3^4)^{\frac{1}{4}}x^{\frac{3}{4}-\frac{2}{4}}}{y^{\frac{1}{4}+\frac{1}{12}}}\implies \cfrac{3^{4\cdot \frac{1}{4}}x^{\frac{1}{4}}}{y^{\frac{4}{12}}}\implies \cfrac{3^{\frac{4}{4}}x^{\frac{1}{4}}}{y^{\frac{1}{3}}}
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\cfrac{3\sqrt[4]{x}}{\sqrt[3]{y}}
7 0
2 years ago
Unit 1 geometry basics quiz 1-3 angle measures and relationships
ASHA 777 [7]

Answer/Step-by-step explanation:

1. Side CD and side DG meet at endpoint D to form <4. Therefore, the sides of <4 are:

Side CD and side DG.

2. Vertex of <2 is the endpoint at which two sides meet to form <2.

Vertex of <2 is D.

3. Another name for <3 is <EDG

4. <5 is less than 90°. Therefore, <5 can be classified as an acute angle.

5. <CDE is less than 180° but greater than 90°. Therefore, <CDE is classified as an obtuse angle.

6. m<5 = 42°

m<1 = 117°

m<CDF = ?

m<5 + m<1 = m<CDF (angle addition postulate)

42° + 117° = m<CDF (Substitution)

159° = m<CDF

m<CDF = 159°

7. m<3 = 73°

m<FDE = ?

m<FDG = right angle = 90°

m<3 + m<FDE = m<FDG (Angle addition postulate)

73° + m<FDE = 90° (Substitution)

73° + m<FDE - 73° = 90° - 73°

m<FDE = 17°

3 0
3 years ago
Part : Find g(x) by identifying the function you are taking the square root of
aksik [14]

Answer:

g(x) = (3x-4)

Step-by-step explanation:

F(x) =  sqrt( 3x-4)

We are taking the square root of (3x-4)

so g(x) = (3x-4)

4 0
2 years ago
Claire is 2 year younger than her sister. The
natta225 [31]

Given:

Claire is 2 year younger than her sister.

The  sum of ages is no less than 44 years.

To find:

Inequality and find the youngest age Claire can  be.

Solution:

Let the age of Claire be x.

Her sister's age = x+2

Sum of their ages is no less than 44 years. It means the sum ages is greater than or equal to 44.

x+(x+2)\geq 44

2x+2\geq 44

2x\geq 44-2

2x\geq 42

Divide both sides by 2.

x\geq 21

It means, Claire age can be greater than or equal to 21. So, the youngest age Claire can  be 21 years old.

Therefore, the required inequality is  2x+2\geq 44 and the correct option is B.

4 0
3 years ago
What is the diameter of a circle with a circumference of 66? Round to the nearest tenth.
Stella [2.4K]
I think the answer is 21 (I don’t know the units)
5 0
2 years ago
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