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sveta [45]
2 years ago
11

The ______ of a function is the complete set of inputs, whereas the _______ is the set of all outputs​

Mathematics
2 answers:
kari74 [83]2 years ago
8 0

Answer:

domain range

Step-by-step explanation:

Drupady [299]2 years ago
5 0

Answer:

Domain, range

Step-by-step explanation:

The <u>domain</u> of a function is the complete set of inputs, whereas the <u>range</u> is the set of all outputs​.

Domain= Input

Range= Output

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So, 4^(1/2) = 2 (or -2)
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The value of the expression is
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Answer:

24

P: parentheses (12 - 8) = 4

E: exponents (3^2) = 9

M: multiplication (12-8)/2 * 4 = 8

D: division (12-8)/2 = 2

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2 years ago
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4 0
3 years ago
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Solving separable differential equation DY over DX equals xy+3x-y-3/xy-2x+4y-8​
Ivanshal [37]

It looks like the differential equation is

\dfrac{dy}{dx} = \dfrac{xy + 3x - y - 3}{xy - 2x + 4y - 8}

Factorize the right side by grouping.

xy + 3x - y - 3 = x (y + 3) - (y + 3) = (x - 1) (y + 3)

xy - 2x + 4y - 8 = x (y - 2) + 4 (y - 2) = (x + 4) (y - 2)

Now we can separate variables as

\dfrac{dy}{dx} = \dfrac{(x-1)(y+3)}{(x+4)(y-2)} \implies \dfrac{y-2}{y+3} \, dy = \dfrac{x-1}{x+4} \, dx

Integrate both sides.

\displaystyle \int \frac{y-2}{y+3} \, dy = \int \frac{x-1}{x+4} \, dx

\displaystyle \int \left(1 - \frac5{y+3}\right) \, dy = \int \left(1 - \frac5{x + 4}\right) \, dx

\implies \boxed{y - 5 \ln|y + 3| = x - 5 \ln|x + 4| + C}

You could go on to solve for y explicitly as a function of x, but that involves a special function called the "product logarithm" or "Lambert W" function, which is probably beyond your scope.

8 0
1 year ago
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