Answer:
Please find the answer below
Explanation:
// Online C compiler to run C program online
#include <stdio.h>
int main() {
// Write C code here
//printf("Hello world");
int userNum;
int i;
int j;
scanf("%d", &userNum);
/* Your solution goes here */
for(i = 0; i<=userNum; i++){
for(j = 0; j <= i; j++){
printf(" ");
}
printf("%d\n", i);
}
return 0;
}
☆ <u>Since, the computer accepts raw data as input and converts into information by means of data processing, it is called information processing machine (IPM).</u>
HOPE IT HELPS ❣️
Answer:
def leap_year_check(year):
return if int(year) % 4 == 0 and (int(year) % 100 != 0 or int(year) % 400 == 0)
Explanation:
The function is named leap_year_check and takes in an argument which is the year which we wish to determine if it's a new year or not.
int ensures the argument is read as an integer and not a float.
The % obtains the value of the remainder after a division exercise. A remainder of 0 means number is divisible by the quotient and a remainder other wise means it is not divisible by the quotient.
If the conditions is met, that is, (the first condition is true and either the second or Third condition is true)
the function leap_year_check returns a boolean ; true and false if otherwise.
The term vulnerability describes the issue that Adam discovered.
b. vulnerability
<u>Explanation:</u>
SQL injection attack is an attack in which an external party can execute SQL commands on the database that serves as a back-end for a particular website. The SQL commands can be used to modify the contents of the website, modify the records, delete the records, and retrieve confidential information as well.
As Adam believes that the code has an issue that allows a SQL injection attack, the term that best describes the issue that he discovered is vulnerability. The website is vulnerable since the code does not have a proper procedure to tackle a situation of SQL injection attack.
<img src=/static/game/image/actions/go.svg alt=' + ugettext(play= button)= += '= style=width: 4%;> ) def noPermissionMessage():