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suter [353]
3 years ago
12

Simplify 5(х+3) – 9х+4 A. 14x7 B. -4x+7 C. -4x+19 D. 14x+19

Mathematics
2 answers:
boyakko [2]3 years ago
6 0

Answer:

The answer is C. -4x+19

goldfiish [28.3K]3 years ago
4 0

Answer:

C

Step-by-step explanation:

start with factoring.

5x+15-9x+4

then solve

-4x+19

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Pls help I don't wanna fail
Andrej [43]

Answer:

115.5

Step-by-step explanation:

385-30%=115.5

8 0
3 years ago
What is the coefficient in this expression? 5 minus 4.7 minus 2 x + StartFraction 5 over 8 EndFraction
Anarel [89]

Answer:

2 is the coefficient

Step-by-step explanation:

2 is the coefficient bc a coefficient is the number next to a variable (such as x)  and 2 is next to x and is the only one in the equation

3 0
3 years ago
Read 2 more answers
Demarcus' workout playlist consists of classic rock songs and rap songs.
Irina18 [472]
It is (13 + 34), (43 + 4). Hope this helps!!! It couldn’t be the other ones because they don’t include all of the numerals.
7 0
3 years ago
If abd = cbd and the perimeter of triangle abd = 12 feet then the perimeter of triangle cbd is
defon
Hey! Let me help you on this one.

In order for us to solve this problem, let's break it apart first.

ABD is congruent to CBD, or in other words, they are the same. 

As it stated, perimeter of ABD is 12 feet, and just like we mentioned before, both of these figures are perfectly congruent.

This means that both of these figures have the same perimeter as well! 

Answer: The perimeter of CBD is 12 feet.


7 0
3 years ago
Place (dlick and drag) one option from each of the lists below Into Its corresponding box to
earnstyle [38]

keeping in mind that perpendicular lines have negative reciprocal slopes, let's check for the slope of the equation above

y = \stackrel{\stackrel{m}{\downarrow }}{-\cfrac{1}{3}}x+5\qquad \impliedby \begin{array}{|c|ll} \cline{1-1} slope-intercept~form\\ \cline{1-1} \\ y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \\\\ \cline{1-1} \end{array} \\\\[-0.35em] ~\dotfill

\stackrel{~\hspace{5em}\textit{perpendicular lines have \underline{negative reciprocal} slopes}~\hspace{5em}} {\stackrel{slope}{\cfrac{-1}{3}} ~\hfill \stackrel{reciprocal}{\cfrac{3}{-1}} ~\hfill \stackrel{negative~reciprocal}{-\cfrac{3}{-1}\implies 3}}

so we're really looking for the equation of a line whose slope is 3 and passes through (1 , 10)

(\stackrel{x_1}{1}~,~\stackrel{y_1}{10})\qquad \qquad \stackrel{slope}{m}\implies 3 \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{10}=\stackrel{m}{3}(x-\stackrel{x_1}{1}) \\\\\\ y-10=3x-3\implies y=3x+7

5 0
2 years ago
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