Answer:
(a) 8.15
(b) 12.92
Step-by-step explanation:
Given: P = $3000, r = 0.085
Where
A is the Amount
P is the Principal
r is the rate
t is the time
(a) For the amount to double, A = 2 × P
A = 2 × $3000
A = $6000
Take 
of both sides
But 
∴ 
t = 8.15
(b) For the amount to double, A = 3 × P
A = 3 × $3000
A = $9000
Take of both sides
But
∴ 
t = 12.92
Answer:
840cm^3
Step-by-step explanation:
[12*15-(12-8)*(15-5)]*6
=[180-40]*6
=140*6
=840cm^3
Answer:
The probability is 0.683
Step-by-step explanation:
To calculate this, we shall be needing to calculate the z-scores of both temperatures
mathematically;
z-score = (x-mean)/SD
From the question mean = 78 and SD = 5
For 73
z-score = (73-78)/5 = -5/5 = -1
For 83
z-score = (83-78)/5 = 5/5 = 1
So the probability we want to calculate is within the following range of z-scores;
P(-1 <z <1 )
Mathematically, this is same as ;
P(z<1) - P(z<-1)
Using the normal distribution table;
P(-1<z<1) = 0.68269 which is approximately 0.683
11 cups of strawberries ... 6 pitchers of juice
x cups of strawberries = ? ... 1 pitcher of juice
If you would like to know what is the number of cups of strawberries in each pitcher, you can calculate this using the following steps:
11 * 1 = 6 * x
11 = 6 * x /6
x = 11/6
x = 1 5/6 cups of strawberries
Result: You will need 1 5/6 cups of strawberries in each pitcher.
We have been given a table of overnight low temperature for a four-day period. We are supposed to give a possible temperature for Wednesday.
We are told that the low temperature on Wednesday was between the second and third highest temperature.
Let us place our given temperatures from least to greatest order.
Sunday (-11), Thursday (-8), Friday (7), Sunday (18)
We can see that second and third highest temperatures are -8 and 7 respectively.
Any number between -8 and 7 will be a possible temperature for Wednesday. 3 can be a possible temperature for Wednesday as 3 is between -8 and 7.
