Answer:
Part 1) 
Part 2) 
Step-by-step explanation:
we know that
The volume of a cube is equal to

where
s is the length of the cube
Part 1)
we have

substitute in the formula


Part 2)
we have

substitute in the formula


Answer:
<h2><u><em>
Letter A</em></u></h2>
Step-by-step explanation:
First of all, we have to solve all the equations
First one is (4*1)-6
<em>We have to use PEMDAS</em>
<em>which stands for </em>
<em>Parenthesis</em>
<em>Exponents</em>
<em>Multiplication</em>
<em>Divison</em>
<em>Addition</em>
<em>Subtraction</em>
In (4*1)-6
You have to do 4*1 first ~ which equals 4
the next step would be 4-6 ~ which equals -2
The next equation would be (1*4)-6
First do 1*4 ~ which is 4
Next 4-6 ~ which again equals -2
Next equation is (1*6)-(4-6)
Parenthesis first, 1*6=6
4-6=-2
6-(-2)
which equals 8
Our next equation is 6-(1*4)
1*4=4
6-4~ which equals 2
Our last equation is 4*(1-6)
Parenthesis comes first, so it would be 1-6 first
which equals -5
4*(-5) would be our final step ~ which equals -20
All of our answers would be
-2 - from the top equation
-2 - from letter A
8 - from letter B
2 - from letter C
-20 - from letter D
which means <u><em>Letter A</em></u> is the answer.
Hope this is helpful.
The roots of the quadratic equation
are
.
Here the given quadratic equation is
. Here
.
The roots are

Answer: 18600 feet
Step-by-step explanation:
f(t)=33600-1500t
f(t)=33600-1500(10)
f(t)=33600-15000
f(t)=18600
D is halfway between A and B
so the coordinates of D are (2,2)
E is halfway between A and C so the coordinates of E are (-1,1)
now you need to find the gradient/slope of DE and BC using the formula:

<h3>
<u>G</u><u>r</u><u>a</u><u>d</u><u>i</u><u>e</u><u>n</u><u>t</u><u> </u><u>o</u><u>f</u><u> </u><u>D</u><u>E</u><u>:</u><u> </u></h3>
SUB IN COORDINATES OF D AND E

therefore the gradient of DE is 1/3.
<h3>
<u>G</u><u>r</u><u>a</u><u>d</u><u>i</u><u>e</u><u>n</u><u>t</u><u> </u><u>o</u><u>f</u><u> </u><u>B</u><u>C</u><u>:</u></h3>
<em>S</em><em>U</em><em>B</em><em> </em><em>I</em><em>N</em><em> </em><em>C</em><em>O</em><em>O</em><em>R</em><em>D</em><em>I</em><em>N</em><em>A</em><em>T</em><em>E</em><em>S</em><em> </em><em>O</em><em>F</em><em> </em><em>B</em><em> </em><em>A</em><em>N</em><em>D</em><em> </em><em>C</em>
<em>
</em>
therefore the gradient of BC is -2/-6 which simplifies to 1/3.
<h3>
therefore, BC and DE are parallel as they both have a gradient/slope of 1/3 and parallel lines have the same gradient</h3>