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Dima020 [189]
3 years ago
9

A star is a swirling mass of dense gases powered by thermonuclear reactions. The great solar furnace transforms 7 million tons o

f mass into energy every second. How many tons of mass will be transformed into energy during the star's 10-billion-year lifetime. Hint: Find the number of seconds in 10 billion years.
Mathematics
1 answer:
marta [7]3 years ago
6 0

Answer:

2.20752 x 10^{24}

Step-by-step explanation:

The first thing you have to do is to look for the number of seconds in one year. You have to multiply 365 days by 86,400 seconds.

  • 365 days refer to the total number of days per year
  • 86,400 seconds refer to the number of seconds per day

Let's solve.

  • 365 x 86,400 = 31,536,000 or 3.1536 x 10^{7}

<em>Therefore, one year has 3.1536 x </em>10^{7}<em> seconds.</em>

Next, you have to know the number of seconds in 10 billion years.

  • (3.1536 x 10^{7}) x  (1.0 x 10^{10}) = 3.1536 x 10^{17}

The last step is to multiply the number of seconds in 10 billion years to 7 million tons of mass per second.

  • (3.1536 x 10^{17}) x 7,000,000 = 2.20752 x 10^{24}
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The manufacturer of hardness testing equipment uses​ steel-ball indenters to penetrate metal that is being tested.​ However, the
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Answer:

Check the explanation

Step-by-step explanation:

Let X denotes steel ball and Y denotes diamond

\bar{x_1} = 1/9( 50+57+......+51+53)

=530/9

=58.89

\bar{x_2}= 1/9( 52+ 56+....+ 51+ 56)

=543/9

=60.33

difference = d =(60.33- 58.89)

=1.44

s^2=1/n\sum xi^2 - n/(n-1)\bar{x}^2

s12 = 1/9( 502+572+......+512+532) -9/8 (58.89)2

=31686/8 - 9/8( 3468.03)

=3960.75 - 3901.53

=59.22

s1 = 7.69

s22 = 1/9( 522+ 562+....+ 512+ 562) -9/8 (60.33)2

=33295/8 - 9/8 (3640.11)

=4161.875 - 4095.12

=66.75

s2 =8.17

sample standard deviation for difference is

s=\sqrt{[(n1-1)s_1^2+ (n2-1)s_2^2]/(n1+n2-2)}

 = \sqrt{[(9-1)*59.22+ (9-1)*66.75]/(9+9-2)}

= \sqrt{1007.76/16}

=7.93

sd = s*\sqrt{(1/n1)+(1/n2)}

=7.93*\sqrt{(1/9)+(1/9)}

=7.93* 0.47

=3.74

For 95% confidence level Z (\alpha /2) =1.96

confidence interval is

d\pm Z(\alpha /2)*s_d

=(1.44 - 1.96* 3.75 , 1.44+1.96* 3.75)

=(1.44 - 7.35 , 1.44 + 7.35)

=(-2.31, 8.79)

There is sufficient evidence to conclude that the two indenters produce different hardness readings.

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3 years ago
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