Answer:
Step-by-step explanation:
if it is linear then it will be a straight line(gradient is the same)
if quadratic then curve(gradeint isnt the same)
y=mx+c
m=[y(2)-y(1)]/[x(2)-x(1)]
you can choose any 2 points from the table
m=2-0.4/0-1
m=-1.6
repeat but 2 different coordinates
m=0.4-0.08/-1--2==>-2.24
m=-2.24
different coordinate therefore quadratic
cant be exponential, because nothing is being raised to some power
Answer:
A. Z = 2 + N13
Step-by-step explanation:
Let's solve your equation step-by-step.
0=z2+4z−9
Step 1: Subtract z^2+4z-9 from both sides.
0−(z2+4z−9)=z2+4z−9−(z2+4z−9)
−z2−4z+9=0
For this equation: a=-1, b=-4, c=9
−1z2+−4z+9=0
Step 2: Use quadratic formula with a=-1, b=-4, c=9.
z=
−b±√b2−4ac
2a
z=
−(−4)±√(−4)2−4(−1)(9)
2(−1)
z=
4±√52
−2
z=−2−√13 or z=−2+√13
Answer:
1) Combine like terms
2) ![\sqrt[3]{x} =3](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Bx%7D%20%3D3)
3) cube both sides of the equation
4) ![4\sqrt[3]{27} +8\sqrt[3]{27}=36](https://tex.z-dn.net/?f=4%5Csqrt%5B3%5D%7B27%7D%20%2B8%5Csqrt%5B3%5D%7B27%7D%3D36)
5) 4(3) + 8(3) = 36
Step-by-step explanation:
1) Combine like terms
2)
3) cube both sides of the equation
4)
5) 4(3) + 8(3) = 36
Answer:
Im choosing A and yes that would be great
Step-by-step explanation:
