The measure of arc GDF is 304°
Solution:
Given data:
m∠CHD = 90°, m(ar EF) = 34°
<em>The angle measure of the central angle is equal to the measure of the intercepted arc.</em>
m∠CHD = m(ar CD) = 90°
<em>Sum of the adjacent angles in a straight line = 180°</em>
⇒ m∠GHC + m∠CHD = 180°
⇒ m∠GHC + 90° = 180°
Subtract 90° from both sides, we get
⇒ m∠GHC = 90°
⇒ m(ar GC) = m∠GHC
⇒ m(ar GC) = 90°
<em>Sum of the adjacent angles in a straight line = 180°</em>
⇒ m∠EHD + m∠CHD = 180°
⇒ m∠EHD + 90° = 180°
Subtract 90° from both sides, we get
⇒ m∠EHD = 90°
⇒ m(ar ED) = m∠EHD
⇒ m(ar ED) = 90°
m(ar GDF) = m(ar GC) + m(ar CD) + m(ar DE) + m( EF)
= 90° + 90° + 90° + 34°
= 304°
The measure of arc GDF is 304°.
35 x -13 x 8 = -3640 - (-6) = -3640 + 6 = -3634
Answer:
x=0 to 1
Step-by-step explanation:
By observation we look at the graph we see that between x=0 and 1; y has the largest slope value 2.
If we calculate the slope for x= 1 to 2 we have :
Slope = y2-y1/ x2-x1 = (3.5-2) / 2-1 = 1.5
Whereas that for x = 0 to 1,
Slope = y2-y1/ x2-x1 = (2-0) / 1-0= 2
What kind of math? algebra? algebra 2?