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lana66690 [7]
3 years ago
8

In one study subjects were randomly given either 500 or 1000 milligrams of vitamin C daily, and the number of colds they came do

wn with during a winter season was noted. In a second study people responded to a questionnaire asking about the average number of hours they sleep per night and the number of colds they came down with during a winter season.
Mathematics
1 answer:
astra-53 [7]3 years ago
5 0

Answer:

<em>A. The first study was an experiment without a control group, while the second was an observational </em>

Step-by-step explanation:

I think your question is missed of key information, allow me to add in and hope it will fit the original one.  

<em>A. The first study was an experiment without a control group, while the second was an observational </em>

<em>study. </em>

<em>B. The first study was an observational study, while the second was a controlled experiment. </em>

<em>C. Both studies were controlled experiments. </em>

<em>D. Both studies were observational studies. </em>

<em>E. None of the above is a correct statement.</em>

My answer:

a. Yes, The first study was an experiment without a control group because it were randomly given either 500 or 1000 milligrams of vitamin C daily, we do not know who was given 500 or 1000.

and

The second was an observational  because we can observe about number of hours they sleep per night and the number of colds.

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Shaded area is 0.9599. Find the indicated z score. The graph depicts the standard normal distribution with mean 0 and standard d
pychu [463]

Answer:

Z-score is 1.75

Step-by-step explanation:

1 - 0.9599 = 0.0401

You can find the Z-score from the standard normal table. Just read the table in reverse.

In this case, Z = 1.75

5 0
3 years ago
The weight, in pounds, of each wrestler on the high school wrestling team at the beginning of the season is listed below.
Vladimir79 [104]

Answer:

(178+142+112+150+206+130) /6

5 0
3 years ago
Hernando and Rachel are factoring 2mp-6p+27-9m. Is either of them correct? Explain your reasoning,
vichka [17]

Answer:

See Explanation

Step-by-step explanation:

The question is incomplete, as Hernando and Rachel's solution are not provided. So, I will just solve the question directly.

Given

2mp-6p+27-9m

Required

Factor

2mp-6p+27-9m

Group into 2

2mp-6p+27-9m = [2mp-6p]+[27-9m]

Factor each group

2mp-6p+27-9m = 2p[m-3]+9[3-m]

Rewrite 3 - m as -(m-3)

So, we have:

2mp-6p+27-9m = 2p[m-3]-9[m-3]

Factor out m - 3

2mp-6p+27-9m = [2p-9][m-3]

3 0
3 years ago
Find the HIGHEST Common<br> and lowest common multple<br> of 36 and 48 using<br> prime factors
Vesnalui [34]

Answer:

Step-by-step explanation:

Least common multiple can be found by multiplying the highest exponent prime factors of 36 and 48. First we will calculate the prime factors of 36 and 48.

Prime Factorization of 36

Prime factors of 36 are 2, 3. Prime factorization of 36 in exponential form is:

36 = 22 × 32

Prime Factorization of 48

Prime factors of 48 are 2, 3. Prime factorization of 48 in exponential form is:

48 = 24 × 31

Now multiplying the highest exponent prime factors to calculate the LCM of 36 and 48.

LCM(36,48) = 24 × 32

LCM(36,48) = 144

List of positive integer factors of 36 that divides 36 without a remainder.

1, 2, 3, 4, 6, 9, 12, 18

Factors of 48

List of positive integer factors of 48 that divides 36 without a remainder.

1, 2, 3, 4, 6, 8, 12, 16, 24

Greatest Common Factor Number

We found the factors and prime factorization of 36 and 48. The biggest common factor number is the GCF number.

So the greatest common factor 36 and 48 is 12.

4 0
3 years ago
Read 2 more answers
The answer to this question
Vinvika [58]

Answer:i cant see it to answer it sorry

Step-by-step explanation:

7 0
4 years ago
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