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Liono4ka [1.6K]
3 years ago
11

Which statement about these two triangles is true?

Mathematics
1 answer:
Sati [7]3 years ago
8 0
It would be a=d, b=c and c=f one. Because it the same triangle but one is just smaller than the other.
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What is does -27/8+ 2n=n- 5/2 + 5/4m=
enyata [817]

Answer:

m= 8n-7/10

Step-by-step explanation:

n- 5/2 + 5/4 m= -27/8 + 2n

n- 5/2 + 5/4 m-n = -27/8 +2n-4

-5/2 +5 /4m=- 27/8 +n

- 5/2 + 5/4 m + 5/2 = - 27/8+n+ 5/2

5/4 m =n- 7/8

4. 5/4 m=4n -4 . 7/8

5m=4n- 7/2

5m/5 = 4n/5 - 7/2 /5

m= 8n-7/10

7 0
3 years ago
A taxi company charges a flat rate of $3.00 in addition to $1.20 per mile. If Anna has no more than $12.00 to spend, which inequ
vitfil [10]

Answer: $3.00+$1.20x ≤ $12.00

8 0
3 years ago
Find the area of each figure below. Round to the nearest hundredth when necessary. 9.6 25.4 m 12 m 10 m
adelina 88 [10]
The First person that wrote there answer is correct
6 0
3 years ago
Which of the following geometric series converges?
Artist 52 [7]

All three series converge, so the answer is D.

The common ratios for each sequence are (I) -1/9, (II) -1/10, and (III) -1/3.

Consider a geometric sequence with the first term <em>a</em> and common ratio |<em>r</em>| < 1. Then the <em>n</em>-th partial sum (the sum of the first <em>n</em> terms) of the sequence is

S_n=a+ar+ar^2+\cdots+ar^{n-2}+ar^{n-1}

Multiply both sides by <em>r</em> :

rS_n=ar+ar^2+ar^3+\cdots+ar^{n-1}+ar^n

Subtract the latter sum from the first, which eliminates all but the first and last terms:

S_n-rS_n=a-ar^n

Solve for S_n:

(1-r)S_n=a(1-r^n)\implies S_n=\dfrac a{1-r}-\dfrac{ar^n}{1-r}

Then as gets arbitrarily large, the term r^n will converge to 0, leaving us with

S=\displaystyle\lim_{n\to\infty}S_n=\frac a{1-r}

So the given series converge to

(I) -243/(1 + 1/9) = -2187/10

(II) -1.1/(1 + 1/10) = -1

(III) 27/(1 + 1/3) = 18

8 0
3 years ago
make m the subject!
Xelga [282]
How to:
a+b-mx=0
a+b=mx
(a+b)/x=m
7 0
2 years ago
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