Answer:
m= 8n-7/10
Step-by-step explanation:
n- 5/2 + 5/4 m= -27/8 + 2n
n- 5/2 + 5/4 m-n = -27/8 +2n-4
-5/2 +5 /4m=- 27/8 +n
- 5/2 + 5/4 m + 5/2 = - 27/8+n+ 5/2
5/4 m =n- 7/8
4. 5/4 m=4n -4 . 7/8
5m=4n- 7/2
5m/5 = 4n/5 - 7/2 /5
m= 8n-7/10
The First person that wrote there answer is correct
All three series converge, so the answer is D.
The common ratios for each sequence are (I) -1/9, (II) -1/10, and (III) -1/3.
Consider a geometric sequence with the first term <em>a</em> and common ratio |<em>r</em>| < 1. Then the <em>n</em>-th partial sum (the sum of the first <em>n</em> terms) of the sequence is

Multiply both sides by <em>r</em> :

Subtract the latter sum from the first, which eliminates all but the first and last terms:

Solve for
:

Then as gets arbitrarily large, the term
will converge to 0, leaving us with

So the given series converge to
(I) -243/(1 + 1/9) = -2187/10
(II) -1.1/(1 + 1/10) = -1
(III) 27/(1 + 1/3) = 18
How to:
a+b-mx=0
a+b=mx
(a+b)/x=m