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Dovator [93]
3 years ago
14

The park shown is in the shape of a square. Is the perimeter rational or irrational? Area = 24,200 yd 2

Mathematics
1 answer:
romanna [79]3 years ago
4 0

Answer:

Perimeter is irrational

<em></em>

Step-by-step explanation:

<em>The attachment is missing but the question is still answerable</em>

Given

Area = 24200 yd^2

Required

Determine if the Perimeter is rational or not

First, we need to determine the sides of the square;

Area = Length * Length

Substitute Area = 24200 yd^2

24200 = Length * Length

24200 = Length^2

Take Square root of both sides

\sqrt{24200} = Length

Length = 155.563492

The perimeter of a square is calculated as:

Perimeter = 4 * Length

Perimeter = 4 * 155.563492

Perimeter = 622.253968

<em>Because the value of </em><em>perimeter </em><em>can't be gotten by dividing two integers, then </em><em>perimeter is irrational</em>

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Use the rules of exponents to simplify the expressions. Match the expression with its equivalent value.
Lelechka [254]

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1) \frac{(-2)^{-5}}{(-2)^{-10}}=-32

2) 2^{-1}.2^{-4} = \frac{1}{32}

3) (-\frac{1}{2} )^3.(-\frac{1}{2} )^2=-\frac{1}{32}

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Step-by-step explanation:

1) \frac{(-2)^{-5}}{(-2)^{-10}}

Solving using exponent rule: a^{-m}=\frac{1}{a^m}

\frac{(-2)^{-5}}{(-2)^{-10}}\\=(-2)^{-5+10}\\=(-2)^{5}\\=-32

So, \frac{(-2)^{-5}}{(-2)^{-10}}=-32

2) 2^{-1}.2^{-4}

Using the exponent rule: a^m.a^n=a^{m+n}

We have:

2^{-1}.2^{-4}\\=2^{-1-4}\\=2^{-5}

We also know that: a^{-m}=\frac{1}{a^m}

Using this rule:

2^{-5}\\=\frac{1}{2^5}\\=\frac{1}{32}

So, 2^{-1}.2^{-4} = \frac{1}{32}

3) (-\frac{1}{2} )^3.(-\frac{1}{2} )^2

Solving:

(-\frac{1}{2} )^3.(-\frac{1}{2} )^2\\=(-\frac{1}{8} ).(\frac{1}{4} )\\=-\frac{1}{32}

So, (-\frac{1}{2} )^3.(-\frac{1}{2} )^2=-\frac{1}{32}

4) \frac{2}{2^{-4}}

We know that: a^{-m}=\frac{1}{a^m}

\frac{2}{2^{-4}}\\=2\times 2^4\\=2(16)\\=32

So, \frac{2}{2^{-4}} = 32

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