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3 years ago

7

Select to rates that are equivalent to 6:10

1 answer:

Advocard [28]3 years ago

4 0

Answer:12:20 And 18:30
I Think these are the answer

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How much is two and two

Sloan [31]

If your question is how much is 2 multipled by 2, then:

2 × 2 = 4

If your question is how much is 2 divided by 2, then:

2 ÷ 2 = 1

If your question is how much is 2 plus 2, then:

2 + 2 = 4

If your question is how much is 2 minus 2, then:

2 - 2 = 0

Hope this helps! :)
Have a lovely day! <3

4 0

3 years ago

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PLS SOMONE HELP<br> ITS HOMEWORK

Anna [14]

Answer:

$4) \: a) \: 5xy \times (3x {}^{2} + 2xy + y {}^{2}) \\ \\ b) \: 2q \times (3p - 2) + 9p - 6 \\ 2q \times (3p - 2) + 3(3p - 2) \\ (3p - 2)(2q + 3)$

3 0

3 years ago

Please help me ASAP!

il63 [147K]

Answer:

B: 153ft2

Step-by-step explanation:

8 0

3 years ago

MATH HELP PLZ!!!

RoseWind [281]

Answer:

a) $tan (157.5) = \frac{1-cos 315}{sin315}$

b)

$sin (165) =\sqrt{ \frac{1-cos (330) }{2}}$

c)

$sin^{2} (157.5) = \frac{1-cos (315) }{2}$

d)

cos 330° = 1- 2 sin² (165°)

Step-by-step explanation:

<u><em>Step(i):-</em></u>

By using trigonometry formulas

a)

cos2∝ = 2 cos² ∝-1

cos∝ = 2 cos² ∝/2 -1

1+ cos∝ = 2 cos² ∝/2

$cos^{2} (\frac{\alpha }{2}) = \frac{1+cos\alpha }{2}$

b)

cos2∝ = 1- 2 sin² ∝

cos∝ = 1- 2 sin² ∝/2

$sin^{2} (\frac{\alpha }{2}) = \frac{1-cos\alpha }{2}$

<u><em>Step(i):-</em></u>

Given

$tan\alpha = \frac{sin\alpha }{cos\alpha }$

we know that trigonometry formulas

$sin\alpha = 2sin(\frac{\alpha }{2} )cos(\frac{\alpha }{2} )$

1- cos∝ = 2 sin² ∝/2

Given

$tan(\frac{\alpha }{2} ) = \frac{sin(\frac{\alpha }{2} )}{cos(\frac{\alpha }{2}) }$

put ∝ = 315

$tan(\frac{315}{2} ) = \frac{sin(\frac{315 }{2} )}{cos(\frac{315 }{2}) }$

multiply with ' 2 sin (∝/2) both numerator and denominator

$tan (\frac{315}{2} )= \frac{2sin^{2}(\frac{315)}{2} }{2sin(\frac{315}{2} cos(\frac{315}{2}) }$

Apply formulas

$sin\alpha = 2sin(\frac{\alpha }{2} )cos(\frac{\alpha }{2} )$

1- cos∝ = 2 sin² ∝/2

now we get

$tan (157.5) = \frac{1-cos 315}{sin315}$

b)

$sin^{2} (\frac{\alpha }{2}) = \frac{1-cos\alpha }{2}$

put ∝ = 330° above formula

$sin^{2} (\frac{330 }{2}) = \frac{1-cos (330) }{2}$

$sin^{2} (165) = \frac{1-cos (330) }{2}$

$sin (165) =\sqrt{ \frac{1-cos (330) }{2}}$

c )

$sin^{2} (\frac{\alpha }{2}) = \frac{1-cos\alpha }{2}$

put ∝ = 315° above formula

$sin^{2} (\frac{315 }{2}) = \frac{1-cos (315) }{2}$

$sin^{2} (157.5) = \frac{1-cos (315) }{2}$

d)

cos∝ = 1- 2 sin² ∝/2

put ∝ = 330°

$cos 330 = 1 - 2sin^{2} (\frac{330}{2} )$

cos 330° = 1- 2 sin² (165°)

3 0

3 years ago

Find the radius of a circle whose area is 78.6 cm squared

kifflom [539]

The radius is 4.99, im sure

4 0

3 years ago

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