3a + 6b = 45
2a - 2b = -12....multiply by 3
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3a + 6b = 45
6a - 6b = - 36 ...(result of multiplying by 3)
---------------add
9a = 9
a = 1
3a + 6b = 45
3(1) + 6b = 45
3 + 6b = 45
6b = 45 - 3
6b = 42
b = 7
solution is : (1,7)
Answer
B) When the x-value is 0, and the y-value is 1
Step-by-step explanation:
Edge
Answer:
i'm not sure so i'm sorry if it is not the right answer
Step-by-step explanation:
Let's assume AC is a straight line and B is on the line between A and C
AC=AB+BC
AC=4x+7+5x-8
AC=9x-1
Step-by-step explanation:
- First, the radical needs to be alone on one side of the equation, if there is - 4, - 3 next to it then you'll have to transfer it to the opposite side like that:
5. (y+7)^0.5 - 4=4
(y+7)^0.5=8......
- Second, you need to square the two sides of the equation :
5.((y+7)^0.5) ^2=8^2
Y+7=64
Y+7-7=64-7
Y=57
Note: if the radical's index is (2) then you'll square the two sides of the equation, but if the index is (3) you'll have to cube the two sides of the equation, "look at the exercises 9,10"