Solve for x and y 3x + 2y = 16 7x + y = 19 (-2,-5) (-2,5) (2,5) (2,-5)

91284 the nearest ten thousand

almond37 [142]

91284 the nearest ten thousand is 9

8 0

3 years ago

Read 2 more answers

Solve for a, b, and c. Will give brainliest and 15 points

Umnica [9.8K]

The answers are:
A= 40°
B= 140°
C=180°

5 0

4 years ago

Solve the system of equations using substitution y=x-1 and y=-2x+5

pav-90 [236]

Since the two equations equal y, set them equal to each other.

x-1=-2x+5

From there, solve for x.

First get x on one side, by using the addition property of equality.

x-1=-2x+5
3x-1=5

Isolate x by adding 1.
3x=6

Lastly get x all by itself by dividing each side by 3.
x=2

You can now substitute your x-value, 2, into one of the equations (or both, if you wish; either one will result in the same answer.)

y=x-1
y=2-1
y=1

OR

y=-2x+5
y=-2(2)+5
y=-4+5
y=1

Final answer:
x=2 and y=1

Any questions or anything you would like me to clarify, feel free to ask :)

7 0

3 years ago

(Refer to the attached image)

RSB [31]

Answer:

missing side: 133 cm

Explanation:

Provided 2 length sides and one angle also need to find one missing side.

So, use cosine rule:

⇒ a² = b² + c² - 2bc cos(A)

Insert values

⇒ g² = 166² + 147² - 2(166)(147) cos(50)

⇒ g² = 17794.3935

⇒ g = √17794.3935

⇒ g = 133.3956

⇒ g = 133 (rounded to nearest whole number)

8 0

2 years ago

An article reports on an experiment in which each of five groups consisting of six rats was put on a diet with a different carbo

loris [4]

Answer:

H0 is rejected, Hence the true average DNA content is affected by the type of carbohydrate in the diet between samples

Step-by-step explanation:

A B C D E

2.58 2.63 2.13 2.41 2.49

∑A=2.58 ∑B=2.63 ∑C=2.13 ∑D=2.41 ∑E=2.49

A² B² C² D² E²

6.6564 6.9169 4.5369 5.8081 6.2001

∑A²=6.6564 ∑B²=6.9169 ∑C²=4.5369 ∑D²=5.8081 ∑E²=6.2001

Calculations

Group A B C D E Total

N n1=1 n2=1 n3=1 n4=1 n5=1 n=5

∑xi T1=2.58 T2=2.63 T3=2.13 T4=2.41 T5=2.49 ∑x=12.24

∑x²i 6.6564 6.9169 4.5369 5.8081 6.2001 ∑x²=30.1184

Mean xi 2.58 2.63 2.13 2.41 2.49 Total2.448

Σ Σ xij^2 = 185.4 given

Let k = the number of different samples = 5

n=n1+n2+n3+n4+n5=1+1+1+1+1=5

Overall ˉx=12.24/5 =2.448

∑x=T1+T2+T3+T4+T5=2.58+2.63+2.13+2.41+2.49=12.24----1

Correction Factor=(∑x)²/n=12.242/5=29.9635--------(2)

∑T²i/ni=(2.582/1+2.632/1+2.132/1+2.412/1+2.492/1)=30.1184------(3)

∑x²=∑x²1+∑x²2+∑x²3+∑x²4+∑x²5

=6.6564+6.9169+4.5369+5.8081+6.2001=30.1184-------(4)

ANOVA:

Step-1 : sum of squares between samples

SSB=(∑T2i/ni)-(∑x)2/n

=(3)-(2)

=30.1184-29.9635

=0.1549

Step-2 : Total sum of squares

SST=SSB-CF

= 185.4-2.488

=182.952

Step-3 : Sum of Squares Within Samples

SSW=∑x²-(∑T²i/ni)=SST- SSB=

= 182.952-0.1549=182.7971

Step-4 : variance between samples

MSB=SSB/k-1

=0.1549/4

=0.0387

Step-5 : variance within samples

MSW=SSW/n-k

=182.7971/5-5

=36.55942

Step-6 : test statistic F for one way ANOVA test

F=MSB/MSW

=0.0387/36.55942 = 0 .001058

ANOVA table

Source Sums Degrees Mean

of Variation of Squares of freedom Squares

SS DF MS F

B/w samples SSB = 0.1549 k-1 = 4 MSB = 0.0387 0.001

Within samples SSW = 0 n-k = 0 MSW = 36.55942

Total SST = 0.1549 n-1 = 4

H0 : The true average DNA content is not affected by the type of carbohydrate in the diet between samples

Ha : The true average DNA content is affected by the type of carbohydrate in the diet between samples

F(4,0) at 0.05 level of significance =0.5

As calculated F=0.001 >0.5

So, H0 is rejected, Hence the true average DNA content is affected by the type of carbohydrate in the diet between samples

6 0

3 years ago