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Aleks04 [339]
2 years ago
10

Estimate the quotient by rounding the expression to relate to a one-digit fact. Explain your thinking in the space below. 1,275

÷ 588 ≈ ___ *
Mathematics
2 answers:
madreJ [45]2 years ago
6 0

Answer:

2 remainder 100

Step-by-step explanation:

1275=1300

588=600

1300/600=2 remainder 100

Norma-Jean [14]2 years ago
5 0
2.1 i think i am not 100% sure
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Quadrilateral QRST, with vertices Q (1, 2), R (3, 4), S (5, 6), and T (2, 7), is dilated by a factor of 2 with the center of dil
bija089 [108]

Answer:

Step-by-step explanation:

Given

Quadrilateral QRST

Q (1, 2), R (3, 4), S (5, 6), and T (2, 7)

Dlated Factor = 2

Required

Coordinates of quadrilateral Q′R′S′T′

<em>Provided that a quadrilateral is dilated with the center of dilation at the origin; the new dilated shape is simply the multiplication of the dilation factor by the coordinates of the original shape;</em>

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In other words,

Q'R'S'T' = Dilation factor * QRST

When Q = (1,2)

Q' = 2 * (1,2)

Q' = (2,4)

When R = (3,4)

R' = 2 * (3,4)

R' = (6,8)

When S = (5,6)

S' = 2* (5,6)

S' = (10,12)

When T= (2,7)

T'  = 2 * (2,7)

T' = (4,14)

Hence, the coordinates of Q'R'S'T' is

Q' = (2,4); R' = (6,8); S' = (10,12); T' = (4,14)

6 0
3 years ago
What is c3/2 if c equal 4?
Sedbober [7]

Answer:

(4 x 3) / 2

Step-by-step explanation:

3 0
3 years ago
A university has 29,970 students. In a random sample of 285 students, 19 speak three or more languages. Predict the number of st
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Set up a proportion.
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4 0
2 years ago
A piece of cardboard measures 10 ft by 10 ft. Four equal squares of size x are removed from the corners. After removing the squa
Gnesinka [82]

Answer:

The value of x would be \frac{5}{3}

Step-by-step explanation:

Given,

The dimension of the cardboard = 10 ft by 10 ft,

∵ After removing four equal squares of size x ( in ft ) from the corners,

The dimension of the resultant box would be,

Length = ( 10 - 2x ) ft,

Width = ( 10 - 2x ) ft,

Height = x ft,

The volume of box,

V=(10-2x)\times (10 - 2x)\times x=x(10-2x)^2 = x(100 - 40x + 4x^2)=100x - 40x^2 + 4x^3

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Again differentiating with respect to x,

V''=-80 + 24x

For maxima or minima,

V'=0

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x=\frac{20\pm \sqrt{20^2-4\times 3\times 25}}{6}

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x=\frac{20\pm \sqrt{100}}{6}

x=\frac{20\pm 10}{6}

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For x = 5/3, V'' = negative,

While for x = 5, V'' = Positive,

Hence, the value of x would be 5/3 ft for maximising the volume.

8 0
3 years ago
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