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sweet-ann [11.9K]
4 years ago
15

The foot of a ladder is placed 6 feet from a wall if the top of the ladder rests 8 feet up on the wall how long is the ladder?

Mathematics
2 answers:
mrs_skeptik [129]4 years ago
5 0
10. You would need to use pythagorean theorem (a^2+b^2=c^2). So it is 6^2+8^2=c^2. Then it is 36+64=c^2. Next, 100=c^2. Square root 100. Answer is 10.
Vlada [557]4 years ago
4 0
Try to imagine this word problem, there is a wall and a ladder leaning against it, the space from the bottom of the ladder is labeled 6 and the length of the height the ladder reaches on the wall is 8. Imagine this as a right triangle now, where the length of the ladder is the hypotenuse and the length of the legs of the triangle is 6 and 8. Because we know this, we can use the Pythagorean theorem, a^2+b^2=c^2
We then plug in the values and you get 6^2+8^2=c^2
When you simplify, you get 36+64=c^2 which is c^2=100
When you solve for c, you get c=10 which would be the length of the ladder :)
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Answer:

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Step-by-step explanation:

To find the distance, set up a proportion. A proportion is two equal ratios set equal to each other. We form the ratios by using corresponding values. We write a ratio of \frac{map}{real world} and simplify.

We know \frac{map}{real world}=\frac{0.5in}{2.3 miles}. We know the distance on the map is 12 cm and 6 cm whish converts to 4.7 inches and 2.4 inches. We can write \frac{4.7in}{xmiles} and  \frac{2.4in}{xmiles}

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2.3(2.4)=0.5(x)\\5.52=0.5x\\\frac{5.52}{0.5}=\frac{0.5x}{0.5} \\11.04 miles=x

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