<span>i Ace</span>hello : let : A(-6,6) B(6,-2) the center is w((-6+6)/2 , (6-2)/2)....(midel <span>[ AB] w(0 ,2) the ridus is : r = AB/2 AB = </span>√(-6-6)²+(6+2)² = √(144+64) =<span>√208/2 </span>an equation in <span>standard form equation of the circle : </span>(x+0)²+(y-2)² = (√208/2)²=208/4 = 52
