Ask question

Ask question

All categories

3 years ago

8

Many teams?

1 answer:

eimsori [14]3 years ago

5 0

Answer:

75 divided by 15 is 7

Step-by-step explanation:

You might be interested in

Drag the tiles to the correct boxes to complete the pairs. Not all tiles will be used. Let f(t) be the number of vinyl records s

KIM [24]

I FOUND YOUR COMPLETE QUESTION IN OTHER SOURCES.
PLEASE SEE ATTACHED IMAGE.

First, we define the variables:
x: number of years after 1950
f (x): amount of vinyl sold.
Then, with the variables defined, we have:

68594 vinyl records were sold in 1958 ---------> f (8) = 68594

91299 vinyl records were sold in 1961 ---------> f (11) = 91299

38720 vinyl records were sold in 1952 ---------> f (2) = 38720

161743 vinyl records were sold in 1967 ---------> f (17) = 161743

5 0

3 years ago

A coin is flipped eight times where each flip comes up either heads or tails. How many possible outcomes a) are there in total?

attashe74 [19]

Answer:

There are 256 ways in total.

There are 56 possible outcomes contain exactly three heads.

The possible outcomes contain at least three heads is 219.

The possible outcomes contain the same number of heads and tails are 70.

Step-by-step explanation:

Consider the provided information.

A coin is flipped eight times where each flip comes up either heads or tails.

Part (a) How many possible outcomes are there in total?

Each time we flip a coin it comes up either heads or tail.

Therefore the total number of ways are:

$2\times 2\times 2\times 2\times 2\times 2\times 2\times 2=2^8=256$

Hence, there are 256 ways in total.

Part (b) contain exactly three heads?

We want exactly 3 heads, therefore,

n=8 and r=3

According to the definition of combination: $\binom{n}{r}=\frac{n!}{r!(n-r)!}$

$\binom{8}{3}=\frac{8!}{3!(5)!}=56$

Hence, there are 56 possible outcomes contain exactly three heads.

Part (c) contain at least three heads?

For 3 heads: $\binom{8}{3}=\frac{8!}{3!(5)!}=56$

For 4 heads: $\binom{8}{4}=\frac{8!}{4!(4)!}=70$

For 5 heads: $\binom{8}{5}=\frac{8!}{5!(3)!}=56$

For 6 heads: $\binom{8}{6}=\frac{8!}{6!(2)!}=28$

For 7 heads: $\binom{8}{7}=\frac{8!}{7!(1)!}=8$

For 8 heads: $\binom{8}{8}=1$

Now add them as shown:

56+70+56+28+8+1=219

Hence, the possible outcomes contain at least three heads is 219.

Part (d) contain the same number of heads and tails?

Same number of heads and tails means that the value of r=4.

Therefore,

$\binom{8}{4}=\frac{8!}{4!(4)!}=70$

Hence, the possible outcomes contain the same number of heads and tails are 70.

6 0

3 years ago

Gerardo made the following scores on his first semester science tests: 80, 85, 85, 87, 97, 100. Which measure would he use in su

Elza [17]

The mean is 89 the median is 86 the mode is 85 Hope this helps!

(technically the mean is like 88.7 so I just rounded up to get 89)

4 0

3 years ago

What is the value of P

tangare [24]

Answer:

a square's inner angles are 360.

and a triangle's inner angles is 180.

so, the blank angle is 94.

47 + 52 is 99, and 99 + 94 is 193.

360 - 193 is 167.

8 0

3 years ago

What is 2.9 as a fraction

Pani-rosa [81]

Answer:

$\frac{29}{10}$

Step-by-step explanation:

8 0

4 years ago