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maw [93]
4 years ago
8

What is the radius and diameter of the following circle?

Mathematics
1 answer:
alexandr1967 [171]4 years ago
7 0
Diameter= 18cm

Radius is half of diameter

Radius=9cm
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Please help with my algebra 1 homework <br><br> thank you
MrRissso [65]

1) Answer:

\frac{4m^{10} }{9n^{18} }

2) Answer:

8m ^{5}

The answer for first equation is, option B.

and the Answer for Second equation is option D.

6 0
3 years ago
The cheerleader section is on the basketball court. Each row requires a section of floor that is 1 ¾ yards by 3 ⅓ yards. How man
Lady_Fox [76]

Answer:

The area of the floor space is equal to 5.83 sq yards.

Step-by-step explanation:

Given that,

Each row requires a section of floor that is 1 ¾ yards by 3 ⅓ yards.

We need to find how many square yards of floor space are taken up by one row of cheerleaders.

We know that, the area of a rectangle is given by :

A = lb

So,

A=\dfrac{7}{4}\times \dfrac{10}{3}\\\\A=5.83\ yards^2

So, the area of the floor space is equal to 5.83 sq yards.

5 0
3 years ago
Find cotθ if tanθ = 2 and 180° &lt; θ &lt; 270° <br> Plz help
Musya8 [376]

Answer:

1/2

Step-by-step explanation:

cotangent is the reciprocal of a tangent

tanθ = 2

cotθ = 1/2

6 0
3 years ago
A lathe is set to cut bars of steel into lengths of 6 cm. The lathe is considered to be in perfect adjustment if the average len
Gnom [1K]

Answer:

t=\frac{5.97-6}{\frac{0.4}{\sqrt{93}}}=-0.723    

E. -0.723

df=n-1=93-1=92  

p_v =2*P(t_{(92)}  

Since the p value is very high we don't have enough evidence to conclude that the true mean for the lengths is different from 6 cm.

Step-by-step explanation:

Information provided

\bar X=5.97 represent the sample mean for the length

s=0.4 represent the sample standard deviation

n=93 sample size  

\mu_o =6 represent the value that we want to test

\alpha=0.05 represent the significance level

t would represent the statistic  

p_v represent the p value for the test

System of hypothesis

We need to conduct a hypothesis in order to check if the lathe is in perfect adjustment (6cm), then the system of hypothesis would be:  

Null hypothesis:\mu = 6  

Alternative hypothesis:\mu \neq 6  

since we don't know the population deviation the statistic is:

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}  (1)  

Replacing in formula (1) we got:

t=\frac{5.97-6}{\frac{0.4}{\sqrt{93}}}=-0.723    

E. -0.723

P value

The degrees of freedom are given by:

df=n-1=93-1=92  

Since is a two tailed test the p value would be:  

p_v =2*P(t_{(92)}  

Since the p value is very high we don't have enough evidence to conclude that the true mean for the lengths is different from 6 cm.

5 0
3 years ago
I dont know how to do math 10 factors
pav-90 [236]

Answer:

10= 1 , 2 , 5 and 10

Step-by-step explanation:

Those are the factors of 10

4 0
3 years ago
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