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3 years ago

10

A rectangular landing pad measures 20' × 25' with a rectangular target on the pad measuring 6' × 8'. What is the geometric proba

bility that a model rocket falling randomly on the pad will land in the target?

1 answer:

BartSMP [9]3 years ago

8 0

Answer:

9.6%

Step-by-step explanation:

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Help help help math math

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Answer:

It is an example of a nonlinear function.

Step-by-step explanation:

Use a graphing calculator or graph the points and try to make a line, as it will not work

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Sound waves with a large distance between A and B would be sound waves that have a large ________ and produce loud sounds. A) am

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a

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Maurinko [17]

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B

Step-by-step explanation:

In this case the method of there being two of the same x values it is NOT a function. Because then there will be two points on top of each other resulting in it not passing the vertical line test on a graph.

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A plane has 360 total seats which are divided into economy class and business class for every 13 seats in economy class there ar

Marta_Voda [28]

Answer:

There are 260 seats in economy class and 100 seats in business class

Step-by-step explanation:

To solve this problem we first have to calculate the fraction of economic and business seats with respect to the total

We are told that every 13 seats in economy class there are 5 seats in business class

13 + 5 = 18

This means that if there are 18 seats 13 will be economic and 5 business

economic seats = 13/18

business seats = 5/18

To find out the number of seats in the airplane of each class, we have to multiply the total number of seats by these fractions

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3 years ago

Can you help with #21 please. I will mark Brainliest.

Leokris [45]

Answer:

A, C, E

Step-by-step explanation:

By analyzing the graph, we can see that the roots are $-2$ and $-4$ .

We now want to find all equations of the form $(x-(-2))(x-(-4))=(x+2)(x+4)=0$ .

This immediately gives C as 1 answer.

We can expand our equation to find other possible solutions!

By the FOIL method: $(x+2)(x+4)=(x)(x)+(2)(x)+(4)(x)+(2)(4)=x^2+6x+8=0$

We can then divide both sides of the equation to find that $-x^2-6x-8=0$ , so A is another answer.

We can complete the square on $x^2+6x+8$ to find the last possible solution.

$x^2+6x+8=x^2+6x+9-9+8=x^2+6x+9-1=(x+3)^2-1=0$ .

We can then multiply both sides of the equation by $4$ to find that $4(x+3)^2-4=0$ , so E is the last answer.

The proof that the other answers don't work is left as an exercise.

So, the answers are A, C, and E, and we're done!

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