To answer this, let's first describe the two areas and obtain the pertinent dimensions from them.
The area of the square hole is 5 cm^2. Since A = s^2, where s is the length of a side of the square, s = +√5 in this situation. +√5 is approx. 2.24 cm.
The area of the round peg is 5 cm^2 also, but the area is calculated using a different formula: A = πr^2, where r is the radius of the circle. Solving for r^2, we get:
r^2 = A/π. Here, r^2 = (5 cm^2)/π = 5π, so that:
r = +√(5π). This is approx. 3.96 cm, and so the diameter is twice that, or 7.93 cm.
So there's plenty of room for the round peg to enter the square hole, but not the other way around!
Answer:
Option (3)
Step-by-step explanation:
Correct steps for the proof are,
Step Statement
1 cos(2x) = 1 - 2sin²(x)
2 Let 2x = θ
3 x = 
4 
5 
6 
7 
8 
There is a mistake in step 6.
Therefore, Option (3) will be the answer.
Answer:
The answer is (e)
Step-by-step explanation:
You know that the total time for one practice is (10+15+10+20+x). You can simplify that by adding like terms to get (55+x). You need that amount multiplied by three because he has 3 practices a week. so therefore you get 3(55+x). You distribute that three to both terms to get the simplest form which is 165 + 3x.
