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3 years ago

HELP ME PLEASE 60 POINTS BRAINLIEST

Mathematics

1 answer:

Misha Larkins [42]3 years ago

5 0

Answer:

im so sorry but i only know the first one the answer in 5 from adding

Step-by-step explanation:

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Leya [2.2K]

Solving for y right?

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3 years ago

PLS HELP ME WITH THIS!!!!!! HOW DID THEY GET 80ft^2

noname [10]

$\huge \boxed{\mathfrak{Question} \downarrow}$

Determine the surface area of the right square pyramid.

$\large \boxed{\mathfrak{Answer \: with \: Explanation} \downarrow}$

The formula for finding the surface area of a right square pyramid is ⇨ b² + 2bl, where

b = base of the right square pyramid
l = slant height of the right square pyramid.

In the given figure,

base (b) = 4 ft.
slant height (l) = 8 ft.

Now, let's substitute the values of b & l in the formula & solve it :-

$\sf \: {b}^{2} + 2bl \\ = \sf \: {4}^{2} + 2 \times 4 \times 8 \\ = \sf \: 16 + 8 \times 8 \\ = \sf \: 16 + 64 \\ = \huge\boxed{\boxed{ \bf 80 \: ft ^{2} }}$

So, the surface area of the right square pyramid is 80 ft².

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B.120 !!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

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