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marshall27 [118]
3 years ago
6

Lol pls help... only 10.2

Mathematics
1 answer:
Burka [1]3 years ago
6 0

Answer:

3) (0,-4) (4,0) (0,4) (-4,0) 4) (-2.5, 2.5) (5.5) (5.-3)

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It is 2.3/2.6/5/24
from least to greatest
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Standard form for y=mx+b​
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that's standard form for slope

Step-by-step explanation:

have a nice day :)

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Need help with Geometry Work.
cricket20 [7]

Answer:

FG = 16

Step-by-step explanation:

we can state that ΔEFG ≅ ΔEHG due to the Angle-Angle-Side postulate

this means that FG = GH

we can use this equation to solve for 'x':

x + 11 = 3x + 1

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8 0
3 years ago
Determine the length and midpoint of the segment whose endpoints are (–15, 9) and (–4, 11).
ch4aika [34]
(-15,9) \\
x_1=-15 \\
y_1=9 \\ \\
(-4,11) \\
x_2=-4 \\
y_2=11 \\ \\
\hbox{the length:} \\
l=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}=\sqrt{(-4+15)^2+(11-9)^2}=\\
=\sqrt{11^2+2^2}=\sqrt{121+4}=\sqrt{125}=\sqrt{25 \times 5}=5\sqrt{5} \\ \\
\hbox{the midpoint:} (\frac{x_1+x_2}{2}, \frac{y_1+y_2}{2}) \\
\frac{x_1+x_2}{2}=\frac{-15-4}{2}=\frac{-19}{2}=-9.5 \\
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(-9.5,10)

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6 0
3 years ago
Read 2 more answers
The coordinates of the endpoints of ab are A(-6,-5) and b(4,0). Point p is on ab. Determine and state the coordinates of point p
qwelly [4]
We have that
<span>A(-6,-5) and B (4,0)

we know that
</span><span>AP:PB is 2:3
so
(2+3)=5
AP=2/5
PB=3/5

step 1
find the x coordinate of P
Px=Ax+AP*ABx
where
Ax is the x coordinate of A
AP is 2/5
ABx is the distance AB in the x coordinate
so
PX=[-6+(2/5)*(4+6)]------>Px=-2

</span>step 2
find the y coordinate of P
Py=Ay+AP*ABy
where
Ay is the y coordinate of A
AP is 2/5
ABy is the distance AB in the y coordinate
so
Py=[-5+(2/5)*(0+5)]------>Py=-3

the point P is (-2,-3)

see the attached figure

6 0
3 years ago
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