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2 years ago

A roundabout of a radius 7 yd laid with a carpet grass. find the area of the roundabout laid with carpet grass

Mathematics

1 answer:

Novay_Z [31]2 years ago

3 0

Area of roundabout = 153.86 yd2

we are given,

radius = 7 yd

Area of circle = π $r^{2}$

= 3.14 × 7× 7

= 153.86 yd2

<h3>What is the area of circle?</h3>

The area of a circle is the space occupied by the circle in a two-dimensional plane. Alternatively, the space occupied within the boundary/circumference of a circle is called the area of the circle. The formula for the area of a circle is A = πr2, where r is the radius of the circle. The unit of area is the square unit,

To learn more about area of circle from the given link

brainly.com/question/14068861

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Determine the equation of the line that passes through the points:

marin [14]

Answer:

y = -2x+8

Step-by-step explanation:

First find the slope

m = ( y2-y1)/(x2-x1)

= ( -4-4)/(6-2)

= -8/4

= -2

The slope is -2

We can use the slope intercept form

y = mx+b where m is the slope and b is the y intercept

y = -2x +b

Using the point ( 2,4)

4 = -2(2) +b

4 = -4+b

Add 4 to each side

4+4 = -4+4+b

8 = b

y = -2x+8

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4 years ago

What is 2 6/8 in fraction

sukhopar [10]

1/3ni who’s your not a

5 0

3 years ago

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Find all zeros of f(x)=x^4-3x^3+6x^2+2x-60 given that 1+3i is a zero of f(x)

Triss [41]

Answer:

The roots of f(x) are: -2, 3, (1+3i) and (1-3i)

Step-by-step explanation:

We are given an expression:

$f(x)=x^4-3x^3+6x^2+2x-60$

(1+3i) is a root of f(x)

We have to find the remaining roots of f(x).

Since, (1+3i) is a root of f(x),

$x-(1+3i)$

is a factor of given expression.

Now, we check if (1 - 3i) is a root of given function.

$f(x)=x^4-3x^3+6x^2+2x-60\\f(1-3i)=(1-3i)^4-3(1-3i)^3+6(1-3i)^2+2(1-3i)-60\\= (28+96i)-3(-26+18i)+6(-8-6i)+2(1-3i)-60 = 0$

Thus, (1-3i) is also a root of given function.

Since, (1-3i) is a root of f(x),

$x-(1-3i)$

is a factor of given expression.

Thus, we can write:

$(x-(1+3i))(x-(1-3i))\text{ is a factor of f(x)}\\x^2-x(1-3i)+x(1+3i)+(1-3i)(1+3i)\text{ is a factor of f(x)}\\x^2-2x+10\text{ is a factor of f(x)}$

Dividing f(x) by above expression:

$\displaystyle\frac{x^4-3x^3+6x^2+2x-60}{x^2-2x+10} = x^2-x-6$

To find the root, we equate it to zero:

$x^2-x-6 = 0\\x^2 - 3x+2x-6=0\\x(x-3)+2(x-3)=0\\(x+2)(x-3) = 0\\x = -2, x = 3$

Thus, the roots of f(x) are: -2, 3, (1+3i) and (1-3i)

4 0

4 years ago

In parallelogram ABCD, AD = 12 in, m∠C = 46º, m∠DBA = 72º. Find the area of ABCD

dmitriy555 [2]

Answer:

The area of parallelogram ABCD is $78.42 \mathrm{in}^{2}$

Explanation:

Given:

AD = 12 in

$m \angle C=46^{\circ}$

$m \angle D B A=72^{\circ}$

To Find:

The area of parallelogram ABCD=?

Solution:

When we construct the parallelogram with the given data, we get a parallelogram formed by 12 cm as one side and an angle with 46 degrees.

The area of the parallelogram can be calculated by $a b * \sin (a n g l e)$

Substituting the value of a=12 we have

$\text { Area of parallelogram }=12 * \text { bsin } 46$

<u>To find the value of b, </u>

We know that area of a triangle can be expressed as,

$\text { Area of triangle }=(A b / 2) \sin (\text {angle})$

So,

$(12 * B D / 2) * \sin 46=(A B * B D / 2) * \sin 72$

Cancelling BD and 2 on both sides we get,

$12 * \sin 46=A B * \sin 72$

$A B=12 * \frac{\sin 46}{\sin 72}$

Therefore,

$b=\frac{12 \sin 46}{\sin 72}$

Substituting the value of b,

$=12 *\left(\frac{12 \sin 46}{\sin 72}\right) * \sin 46$

=78.42

So the area of the parallelogram is $78.42 \mathrm{in}^{2}$

6 0

4 years ago

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Can 34/8 as a fraction be reduced?

pogonyaev

Answer:it would be 17/4 reduced , but cannot be reduced any farther because 17 is a prime number. Although, you can change it to 4 1/4

Step-by-step explanation:

5 0

4 years ago