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3 years ago

May you give me the answer to this please ?

Mathematics

1 answer:

Mrac [35]3 years ago

8 0

Answer:

using pythagoras theorem

H^2=P^2+B^2

here h=MN ,opposite(P) be 15 and adjacent(B) be 16

(MN)2=15^2+16^2

(MN)^2=225+256

MN= $\sqrt{481}$

MN=21.93

after rounding off MN=21.9

Step-by-step explanation:

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3 years ago

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denis-greek [22]

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3 years ago

Solve for x. 12 = x + 3 X=_____

alexandr1967 [171]

For this case we must find the value of the variable "x" of the following equation:

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So, we follow the steps:

Subtracting 3 from both sides of the equation we have:

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3 years ago

12R If V= ---- (r+R) Make R the subject of the equation .

k0ka [10]

V= $\frac{12R}{r+R}$
note, r and R are differnt
so multipl both sides by (r+R)
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Vr=12R-VR
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divide both sides by (12-V)
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