-3x-3 = 4x-3
-3 = 7x-3
0 = 7x
x = 0
Answer:
use pythagorean's theorem; x=6
Step-by-step explanation:
a^2 + b^2 = c^2
a=length; b(x)=height; c= hypotenuse (longest side)
8^2 + b^2 = 10^2
64 + b^2 = 100 (subtract 64 from each side)
b^2= 36
6 x 6 = 36 so b=6
x=6
X<span>(6 + </span>x)(x<span> + -4) = 24x ... + 2x</span>2<span> + </span>x3<span> = 0 </span>Factor out<span> the Greatest Common Factor (GCF), '</span>x<span>'. </span>x<span>(-48 + 2x + </span>x2<span>) = 0 ... Set the factor '(-8 + -1x)' equal to zero and attempt to </span>solve<span>: Simplifying -8 + -1x = 0 ... box </span>will<span> make the calculator automatically</span>solve<span> for the first variable it sees.</span>
Answer:
15. y -13 = -2(x +7)
16. y -6 = (-3/4)(x +4)
17. y +11 = 4(x +5)
18. y -8 = (-5/3)(x +6)
Step-by-step explanation:
It looks to me like you have the right idea in each case, but have made mistakes with signs or parentheses. Neatness and attention to detail count for a lot.
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You obviously know that the point-slope form of the equation of a line with slope m through point (h, k) is ...
y -k = m(x -h)
In problems 15 and 16, the given slopes are negative. Your equations seem to have missed that fact.
15. m = -2, (h, k) = (-7, 13). y -13 = -2(x +7)
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16. m = -3/4, (h, k) = (-4, 6). y -6 = (-3/4)(x +4)
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It is clear you know that slope is computed as ...
m = (y2 -y1)/(x2 -x1)
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17. m = (1 -(-11))/(-2-(-5)) = 12/3 = 4; (h, k) = (-5, -11). y +11 = 4(x +5)
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18. m = (-7-8)/(3-(-6)) = -15/9 = -5/3; (h, k) = (-6, 8). y -8 = (-5/3)(x +6)
<h3>
Answer:</h3>
<u>Given equation</u> :- 6m² + 7n
where,
- <u>Constant</u> = 0.
- <u>Variable</u> = m, n.
- <u>Terms</u> = 6m² , 7n.
