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scoundrel [369]
3 years ago
7

80% of an airline's flights depart on-time and 20% do not. Of those that depart on-time, 95% arrive on-time. Of those that depar

t late, 10% arrive on-time. What is the chance of someone taking a flight that will arrive on-time?
Mathematics
1 answer:
Dmitry_Shevchenko [17]3 years ago
4 0

Answer:

0.78

Step-by-step explanation:

given that 80% of an airline's flights depart on-time and 20% do not.

Of those that depart on-time, 95% arrive on-time. Of those that depart late, 10% arrive on-time

Let A be the event that flight departs on time.

Now A and A' are mutually exclusive and exhaustive

Let B be the event the flight arrives on time

Using total probability calculation we have

the chance of someone taking a flight that will arrive on-time

= P(B)

=P(A)+P(A'B)\\= 0.80(0.95) +0.20(0.10)\\= 0.76+0.02\\=0.78

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Help with this work pls​
Travka [436]

Answer:

  (6, 2), (0, -2), (-3, -4)

Step-by-step explanation:

The intercepts are clearly (0, -2) and (3, 0). This eliminates the bottom two choices.

Both of these are listed in the upper left choice, but the third point there, (-6, -5), is not on the graph. This leaves only the upper right choice. Checking the remaining two points in that choice, (6, 2) and (-3, -4), confirms they are both on the graph.

8 0
2 years ago
Four times a first number decreased by a second number is - 14. The first
mel-nik [20]

Answer:

f = -5, s = -6

Step-by-step explanation:

F= first number

S= second number

4f - s = -14

f + 3s = -23

3(4f - s = -14)

12f - 3s = -42

+ f + 3s = -23

13f = -65

————

13

f = -5

4f - s = -14

4(-5) - s = -14

-20 - s = -14

+20 +20

-s = 6

———

-1

s = -6

3 0
2 years ago
−62 − (−25)=<br> A) (-87)<br> B) (-37)<br> C) 37<br> D) 87
vaieri [72.5K]

The answer is B) (-37)


3 0
3 years ago
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AB is the angle bisector of CAD. Solve for the missing variable?
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Answer:

x=8^\circ

Step-by-step explanation:

A bisector is the line that divides an angle (which in this case is \angle CAD) exactly in half. Therefore, \angle CAB = \angle BAD and as such we can solve for x:

\angle CAB &= \angle BAD\\33^\circ &= 4x + 1^\circ\\4x = 32^\circ\\x = 8^\circ

and we are done.

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