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drek231 [11]
3 years ago
15

Num teste de resistência de um para-choques, um automóvel de 2300 kg que circula a 15 m/s, embate num obstáculo. Sabendo que a c

olisão durou 0,54 s, determina a intensidade média da força que atuou no automóvel.
Mathematics
1 answer:
Viktor [21]3 years ago
7 0

Responder:

63.888,89N

Explicación paso a paso:

Fuerza = m (v-u) / t

m es la masa = 2300 kg

v es la velocidad final = 15 m / s

u es la velocidad inicial = 0 m / s

t es el tiempo = 0.54s

Sustituir

F = 2300 (15-0) /0,54

F = 2300 (15) /0,54

F = 34500 / 0,54

F = 63.888,89N

Por lo tanto, la intensidad de la fuerza que no está motorizada es 63,888.89N

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