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3 years ago

8

PLEASE HELP ME!! I AM HAVING SO MUCH PROBLEMS!!

1 answer:

kotykmax [81]3 years ago

3 0

1) For a quadratic equation, we'll have two answers typically. We're looking for two numbers that when multiplied give -64, and when added give -12. This is a bit of trial and error, but you go about it by systematically factoring -64 in all possible combinations: 64=-2*32=2*-32=-4*16=4*-16=-8*8. Of these, I can 'see' that I can make -12 with 4 and -16. So the factorization of the equation becomes:

(x-16)(x+4)=0, so x=16 or x=-4.

Answers B and D are correct.

For (2), same trick applies. Rewrite as x²-8x-48=0. Factor as (x+4)(x-12)=0 because 4*-12=-48 and 4-12=-8. The other solution is x=12.

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Help pls!?!?!?!!! This is algebra 2

Tresset [83]

$\boxed{\sf a_n=\dfrac{(-1)^n}{5n}}$

a:-

$\\ \sf\longmapsto a_1=\dfrac{(-1)^1}{5(1)}$

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b:-

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3 years ago

9 exponent 10<br> Divide by 9 exponent 11

Natasha_Volkova [10]

Answer:

$\frac{\sqrt{110} }{11}$ or $\frac{\sqrt{10} }{\sqrt{11} }$

Step-by-step explanation:

I assume you mean $\frac{9\sqrt{10} }{9\sqrt{11} }$

there is a common factor of 9 in the numerator and denominator so we can cancel out to form $\frac{\sqrt{10} }{\sqrt{11} }$

$\frac{\sqrt{10} }{\sqrt{11} }$ is technically a correct answer, but I will go ahead to rationalize the denominator

multiply $\frac{\sqrt{10} }{\sqrt{11} }$ by some form of 1. this case, we will use $\frac{\sqrt{11} }{\sqrt{11} }$ as our 1.

$\frac{\sqrt{10} }{\sqrt{11} }$ * $\frac{\sqrt{11} }{\sqrt{11} }$ = $\frac{\sqrt{10} *\sqrt{11} }{\sqrt{11} *\sqrt{11} }$ = $\frac{\sqrt{110} }{11}$

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3 years ago