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Norma-Jean [14]
3 years ago
6

Are these triangles congruent? If so, state the rule which you used to determine congruence

Mathematics
1 answer:
Zepler [3.9K]3 years ago
3 0

Answer:

not necessarily confident cuz simply it doesn't look same size it should be similar

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Based on past experience, a bank believes that 8.9 % of the people who receive loans will not make payments on time. The bank ha
love history [14]

Answer:

To be able to approximate the sampling distribution with a normal model, it is needed that np \geq 10 and n(1-p) \geq 10, and both conditions are satisfied in this problem.

Step-by-step explanation:

For each person, there are only two possible outcomes. Either they will make payments on time, or they won't. The probability of a person making the payment on time is independent of any other person, which means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

Probability of exactly x successes on n repeated trials, with p probability.

The sampling distribution can be approximated to a normal model if:

np \geq 10 and n(1-p) \geq 10

Based on past experience, a bank believes that 8.9 % of the people who receive loans will not make payments on time.

This means that p = 0.089

The bank has recently approved 220 loans.

This means that n = 220

What must be true to be able to approximate the sampling distribution with a normal model?

np = 220*0.089 = 19.58 \geq 10

n(1-p) = 220*0.911 = 200.42 \geq 10

To be able to approximate the sampling distribution with a normal model, it is needed that np \geq 10 and n(1-p) \geq 10, and both conditions are satisfied in this problem.

3 0
3 years ago
A box has a volume of 308 cm cubed. Its height is 4 cm greater than its length. Its length is 3 cm greater than its width. What
kifflom [539]

Answer:

4 cm.

Step-by-step explanation:

Given:

A box has a volume of 308 cm cubed.

Its height is 4 cm greater than its length.

Its length is 3 cm greater than its width.

Question asked:

What is the width of the box?

<u>Solution</u>:

Let width  = x\ cm

Length = x+3\ cm

Height = x+3+4=x+7\ cm

<u>As we know:</u>

<u />Volume\ of\ box=length\times width\times height

308=(x+3)\times x\times(x+7)\\ \\ 308=(x^{2} +3x)(x+7)\\ \\ 308=x^{2} (x+7)+ 3x(x+7)\\ \\ 308=x^{3} +7x^{2} +3x^{2} +21x\\ \\ 308=x^{3} +10x^{2} +21x\\ \\ Subtract\ 308\ from\ both\ sides\\ \\ x^{3} +10x^{2} +21x-308=0\\ \\ factor\ left\ side\ of\ equation\\ \\ (x-4)(x^{2} +14x+77)=0\\ \\  Set\ factors\ equal\ to\ 0.\\ \\ x-4=0 \ or\  x^{2} +14x+77=0\\ \\ \\

As width can never be in negative, x= 4\ cm

By substituting the value:-

Width  = x\ cm = 4 cm

Thus, width of the box is 4 cm.

4 0
3 years ago
Antonio invests 3000 at .10 interest compounded semianually for 12 years. Use the compound interest formula to calculate the com
marissa [1.9K]

Answer:

A=9675.299

Step-by-step explanation:

A=p(1+r)^t

A compound amount

P is the principle amount invested

r : rate ( semiannually is 0.5 )

t=years ( semiannually 12*2=24)

A=3000(1+0.10/2)^24

A=9675.299

8 0
3 years ago
What is your debt ratio? If you budget $375 to payoff your credit card debt and you payoff the highest interest card first while
irga5000 [103]
The debt ratio on the Murk is 45% 
<span>The debt ratio on the Mini is 90% </span>
<span>The average between the two is 63% </span>

<span>Payoff are estimates only. Paying $375/mo with the highest interest rate first will have the Mini @ $50/mo paid off by Jul 2016 and the Murk @ $326/mo paid off by Sep 2016. What you'll do is pay the minimum on the lowest interest rate card and apply the remainder of the $375 budget to the highest interest rate card. When the Mini is paid off, combine that payment with the Murk and continue wit the $375 payments.</span>
4 0
3 years ago
Draw the following triangle after a 90° clockwise rotation about the origin.
slamgirl [31]

Answer:

Its gonna be in the same spot but just on the left

Step-by-step explanation:

5 0
3 years ago
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