Question

Find the product of 3 and the linear equation, and solve for both equations for y.

Answer 1

Answer:

Part 1) The product of 3 and 2y-4x=8 is $6y-12x=24$

Part 2) The original equation in slope intercept form is $y=2x+4$

Part 3) The new equation in slope intercept form is $y=2x+4$

Step-by-step explanation:

we have

$2y-4x=8$

step 1

Find out the product of 3 and 2y-4x=8

Multiply both sides by 3

$3(2y-4x)=3(8)$

Apply distributive property both sides

$6y-12x=24$

step 2

Find out the original equation in slope intercept form

The equation of the line in slope intercept form is

$y=mx+b$

we have

$2y-4x=8$

Solve for y

That means ----> Isolate the variable y

Adds 4x both sides

$2y=4x+8$

Divide by 2 both sides

$y=(4x+8)/2$

Simplify

$y=2x+4$

step 3

Find out the new equation in slope intercept form

The equation of the line in slope intercept form is

$y=mx+b$

we have

$6y-12x=24$

Solve for y

That means ----> Isolate the variable y

Adds 12x both sides

$6y=12x+24$

Divide by 6 both sides

$y=(12x+24)/6$

Simplify

$y=2x+4$