Kindly find complete question attached below
Answer:
Kindly check explanation
Step-by-step explanation:
Given a normal distribution with ;
Mean = 36
Standard deviation = 4
According to the empirical rule :
68% of the distribution is within 1 standard deviation of the mean ;
That is ; mean ± 1(standard deviation)
68% of subjects :
36 ± 1(4) :
36 - 4 or 36 + 4
Between 32 and 40
2.)
95% of the distribution is within 2 standard deviations of the mean ;
That is ; mean ± 2(standard deviation)
95% of subjects :
36 ± 2(4) :
36 - 8 or 36 + 8
Between 28 and 44
3.)
99% is about 3 standard deviations of the mean :
That is ; mean ± 3(standard deviation)
99% of subjects :
36 ± 3(4) :
36 - 12 or 36 + 12
Between 24 and 48
Answer:
1.4
Step-by-step explanation:
Fret seems like the best option.
Answer:
The area of the clock ![= 315.41\ inch^{2}](https://tex.z-dn.net/?f=%3D%20315.41%5C%20inch%5E%7B2%7D)
Step-by-step explanation:
We have been given the face of the clock that is ![63\ in](https://tex.z-dn.net/?f=63%5C%20in)
So that is also the circumference of the clock.
Since the clock is circular in shape.
So ![2\pi(r)=63\ inch](https://tex.z-dn.net/?f=2%5Cpi%28r%29%3D63%5C%20inch)
From here we will calculate the value of radius
of the clock that is circular in shape.
Then ![2\pi(r)=63\ inch =\frac{63}{2\pi} = 10.02\ in](https://tex.z-dn.net/?f=2%5Cpi%28r%29%3D63%5C%20inch%20%3D%5Cfrac%7B63%7D%7B2%5Cpi%7D%20%3D%2010.02%5C%20in)
Now to find the area of the clock we will put this value of (r) in the equation of area of the circle.
Now ![\pi (r)^{2}=\pi(10.02)^{2}=315.41\ in^{2}](https://tex.z-dn.net/?f=%5Cpi%20%28r%29%5E%7B2%7D%3D%5Cpi%2810.02%29%5E%7B2%7D%3D315.41%5C%20in%5E%7B2%7D)
So the area of the face of the clock =![315.41\ in^{2}](https://tex.z-dn.net/?f=315.41%5C%20in%5E%7B2%7D)
log_10 (600) is between 2 and 3
2,77815