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AfilCa [17]
3 years ago
6

The area of a regular hexagon is 50 in.2 Find the length of a side. Round your answer to the nearest tenth.

Mathematics
1 answer:
katrin2010 [14]3 years ago
6 0

The answer go be C .7.6

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Answer:   \bold{-7+2\sqrt{14}+5\sqrt{7}-10\sqrt{2}}

<u>Step-by-step explanation:</u>

\dfrac{\sqrt7-5}{\sqrt7+\sqrt8}\bigg(\dfrac{\sqrt7-\sqrt8}{\sqrt7-\sqrt8}\bigg)=\dfrac{7-2\sqrt{14}-5\sqrt{7}+10\sqrt2}{7-8}=\dfrac{7-2\sqrt{14}-5\sqrt{7}+10\sqrt2}{-1}\\\\\\=\boxed{-7+2\sqrt{14}+5\sqrt{7}-10\sqrt2}

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