Answer:
Explained
Explanation:
Cutting tools:
1. Cutting tools can either be single point or multi point.
2. Cutting tools can have variety of material depending on use like ceramics, diamonds, metals, CBN, etc.
3.Cutting tools have definite shapes and geometry.
Abrasive machining tools
1. Abrasive tools are always multi point tools.
2. Abrasive tools composed of abrasives bounded in medium of resin or metal.
3. They do not have definite geometry of shape
Answer:
t= 9.79 hr
Explanation:
Given that
V= 3.5 V
Capacity= 4 Amp-hour
We know that
V= IR
V= Voltage
I =Current
R=Resistance
V = I R
The total voltage on the batteries will be 2 V
2 x 3.5 = I x 10
I= 0.7 A
We know that Power P
P = V I
P = 0.7 x 7
P =4.9 W
4 A.h and 12 volt power supply = 4 x 12 = 48 W.hr
So time of drain t
4.9 t = 48
t= 9.79 hr
Both technicians are correct because all the friction components of a disc brake are exposed to the airstream and this helps to cool the brake parts and maintain braking effectiveness during repeated hard stops from high speeds.
<h3>What is friction?</h3>
Friction can be defined as a force that resists the relative motion of two physical objects when there surfaces come in contact. This ultimately implies that, friction prevents two surface from easily sliding over or slipping across one another.
<h3>What is a braking system?</h3>
A braking system can be defined as a mechanical system which comprises various components that are designed and developed to bring an automobile vehicle in motion to a stop, when applied by a driver.
Generally, when the friction components which makes up a disc brake are exposed to the airstream, it helps to cool the brake parts, as well as to maintain braking system effectiveness in an automobile vehicle, during repeated hard stops from high speeds.
Read more on braking system here: brainly.com/question/24751467
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Answer:
The required cross-sectional area of the copper wires used to connect the source to the mine lights is 0.029mm²
Explanation:
Given.
Copper Resistivity = 1.69 *10^-8Ωm
The mine lights use a total of 5 kW and operate at 120 V dc.
So,
Power = 5kW
Power Required = 5% of 5kW
Power Required = 0.05 of 5000W
Power Required = 250W
Calculating the Resistance
The power lost in the wires is given by 120² / R, where R is the resistance.
250 = 120²/R
R = 120²/250
R = 57.6 Ω
This is small amount over 100 m.
Calculating the Cross-sectional area.
The resistance of the wires is given by:
R = 1.69 * 10^(-8) *100 / A
R = 1.69 * 10^-6/A, where A is the cross-sectional area.
1.69 * 10^(-6)/A = 57.6
A = 1.69 * 10^-6/57.6
A = 2.9340277777777E−8m²
A = 0.029mm²