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timofeeve [1]
2 years ago
5

Linear Time Invariant Systems For each of the systems below an input x(t) and the output y(t) are plotted. Determine whether eac

h of these are linear time invariant (LTI) systems, and can be described by a convolution. Provide an argument for your answer. Note that some cases are described in the time domain, and some in the frequency domain.
Engineering
1 answer:
STALIN [3.7K]2 years ago
4 0

Answer:

The system can be described by a convolution

Explanation:

Thinking process:

If we consider a discrete input to a linear time-invariant system, then the system will be periodic with respect to the period, say N. This therefore, means that the output must also  be periodic. The proof is as follows:

The LTI system can be written for the system where:

y (n+N) = ∑h(k)x(n + N - k)

            = ∑h(k)x(n-k)\\= y(n)

From the proof, it turns out that y(y + N) = y(n) for any value of n, then the output will be the periodic with the period N.

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siniylev [52]

Answer:

wind vane if it can be used to show wind speed and the other is a

Explanation:

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5 0
2 years ago
What is the definition of comma
masya89 [10]
Com·ma
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NOUN
1. a punctuation mark (,) indicating a pause between parts of a sentence. It is also used to separate items in a list and to mark the place of thousands in a large numeral.

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5 0
2 years ago
The capacity of a battery is 1800 mAh and its OCV is 3.9 V. a) Two batteries are placed in series. What is the combined battery
Lynna [10]

Answer:

capacity  = 0.555 mAh

capacity  = 3600 mAh

Explanation:

given data

battery = 1800 mAh

OCV = 3.9 V

solution

we get here capacity when it is in series

so here Q = 2C  

capacity  = 2 × ampere × second   ...............1

put here value and we get

and 1 Ah = 3600 C

capacity  = \frac{2}{3600}

capacity  = 0.555 mAh

and

when it is in parallel than capacity will be

capacity = Q1 +Q2   ...............2

capacity  = 1800 + 1800

capacity  = 3600 mAh

3 0
3 years ago
Match each context to the type of the law that is most suitable for it.
Bas_tet [7]

Answer:

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Explanation:

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5 0
3 years ago
A fatigue test was conducted in which the mean stress was 90 MPa (13050 psi), and the stress amplitude was 190 MPa (27560 psi).
Gwar [14]

Answer:

a) 280MPa

b) -100MPa

c) -0.35

d) 380 MPa

Explanation:

GIVEN DATA:

mean stress \sigma_m = 90MPa

stress amplitude \sigma_a = 190MPa

a) \sigma_m =\frac{\sigma_max+\sigma_min}{2}

    90 =\frac{\sigma_{max}+\sigma_{min}}{2} --------------1

\sigma_a =\frac{\sigma_{max}-\sigma_{min}}{2}

   190 = \frac{\sigma_{max}-\sigma_{min}}{2} -----------2

solving 1 and 2 equation we get

\sigma_{max} = 280MPa

b) \sigma_{min} = - 100MPa

c)

stress ratio=\frac{\sigma_{min}}{\sigma_{max}}

=\frac{-100}{280} = -0.35

d)magnitude of stress range

                      =(\sigma_{max} -\sigma_{min})

                       = 280 -(-100) = 380 MPa

3 0
3 years ago
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