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timofeeve [1]
3 years ago
5

Linear Time Invariant Systems For each of the systems below an input x(t) and the output y(t) are plotted. Determine whether eac

h of these are linear time invariant (LTI) systems, and can be described by a convolution. Provide an argument for your answer. Note that some cases are described in the time domain, and some in the frequency domain.
Engineering
1 answer:
STALIN [3.7K]3 years ago
4 0

Answer:

The system can be described by a convolution

Explanation:

Thinking process:

If we consider a discrete input to a linear time-invariant system, then the system will be periodic with respect to the period, say N. This therefore, means that the output must also  be periodic. The proof is as follows:

The LTI system can be written for the system where:

y (n+N) = ∑h(k)x(n + N - k)

            = ∑h(k)x(n-k)\\= y(n)

From the proof, it turns out that y(y + N) = y(n) for any value of n, then the output will be the periodic with the period N.

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Drivers education - Unit 3
melamori03 [73]

The following scenarios are pertinent to driving conditions that one may encounter. See the following rules of driving.

<h3>What do you do when the car is forced into the guardrail?</h3>

Best response:

  • I'll keep my hands on the wheel and slow down gradually.
  • The reason I keep my hands on the steering wheel is to avoid losing control.
  • This will allow me to slowly back away from the guard rail.
  • The next phase is to gradually return to the fast lane.
  • Slamming on the brakes at this moment would result in a collision with the car behind.

Scenario 2: When driving on a wet road and the car begins to slide

Best response:

  • It is not advised to accelerate.
  • Pumping the brakes is not recommended.
  • Even lightly depressing and holding down the brake pedal is not recommended.
  • The best thing to do is take one foot off the gas pedal.
  • There should be no severe twists at this time.

Scenario 3: When you are in slow traffic and you hear the siren of an ambulance behind

Best response:

  • The best thing to do at this moment is to go to the right side of the lane and come to a complete stop.
  • This helps to keep the patient in the ambulance alive.
  • It also provide a clear path for the ambulance.
  • Moving to the left is NOT recommended.
  • This will exacerbate the situation. If there is no place to park on the right shoulder of the road, it is preferable to stay in the lane.

Learn more about rules of driving. at;

brainly.com/question/8384066

#SPJ1

4 0
2 years ago
What is the name of the device fitted underneath the rear bumper on some cars for either purposes of appearance or to increase a
Mariulka [41]

Answer:

Protruding feelers

Explanation:

5 0
2 years ago
If an object moves 2 meters to the left in 1 second, what is the velocity of the object?
tresset_1 [31]

Answer:

Explanation:

possibly -4

7 0
3 years ago
What website is the bets for paper planes ?
poizon [28]

Answer:

https://www.origamiway.com/paper-airplane-instructions.shtml

Explanation:

This is a more personal preference, so at the end of the day it is what works best for you :D

Hope this helps!

3 0
4 years ago
Consider a voltage v = Vdc + vac where Vdc = a constant and the average value of vac = 0. Apply the integral definition of RMS t
Anna11 [10]

Answer:

Proof is as follows

Proof:

Given that , V = V_{ac} + V_{dc}

<u>for any function f with period T, RMS is given by</u>

<u />RMS = \sqrt{\frac{1}{T}\int\limits^T_0 {[f(t)]^{2} } \, dt  }<u />

In our case, function is V = V_{ac} + V_{dc}

RMS = \sqrt{\frac{1}{T}\int\limits^T_0 {[V_{ac} + V_{dc}]^{2} } \, dt  }

Now open the square term as follows

RMS = \sqrt{\frac{1}{T}\int\limits^T_0 {[V_{ac}^{2} + V_{dc}^{2} + 2V_{dc}V_{ac}] } \, dt  }

Rearranging  terms

RMS = \sqrt{\frac{1}{T}\int\limits^T_0 {V_{dc}^{2}  } \, dt  + \frac{1}{T}\int\limits^T_0 {V_{ac}^{2}  } \, dt  + \frac{1}{T}\int\limits^T_0 {2V_{dc}V_{ac}  } \, dt  }

You can see that

  • second term is square of RMS value of Vac
  • Third terms is average of VdcVac and given is that                      average of  V_{ac}V_{dc} = 0

so

RMS = \sqrt{\frac{1}{T}TV_{dc}^{2}   + [RMS~~ of~~ V_{ac}]^2 }

RMS = \sqrt{V_{dc}^{2}   + [RMS~~ of~~ V_{ac}]^2 }

So it has been proved that given expression for root mean square (RMS) is valid

7 0
3 years ago
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