Answer:
The value of pressure at an altitude of 10000 ft = 10 
Step-by-step explanation:
Given data
Atmospheric pressure 
= 14.7
Pressure at 4000 ft = 12.6
If temperature is constant then the atmospheric pressure is varies with the altitude according to law
P (h) = 
------ (1)
where k= constant & h = height
12.6 = 14.7 
0.857 =
㏑ 0.857 = - 4000 k
-0.154 = - 4000 k
k = 3.85 × 
Thus the atmospheric pressure at an altitude of 10,000 ft is
14.7 × ----- (2)
Product of k & h is
k h = 3.85 × × 10000
k h = 0.385
Put his value of k h = 0.385 in equation (2) we get
14.7 × 
10
This is the value of pressure at an altitude of 10000 ft.
7.2 would be bigger than 7.09
About 90 maybe but not sure
Answer:
t as a function of height h is t = √600 - h/16
The time to reach a height of 50 feet is 5.86 minutes
Step-by-step explanation:
Function for height is h(t) = 600 - 16t²
where t = time lapsed in seconds after an object is dropped from height of 600 feet
t as a function of height h
replacing the function with variable h
h = 600 - 16t²
Solving for t
Subtracting 600 from both side
h - 600 = -16t²
Divide through by -16
600 - h/ 16 = t²
Take square root of both sides
√600 - h/16 = t
Therefore, t = √600 - h/16
Time to reach height 50 feet
t = √600 - h/16
substituting h = 50 in the equation
t = √600 - 50/16
t = √550/16
t= 34.375
t = 5.86 minutes
Answer:
x<5/2
Step-by-step explanation:
We have
2x−3<2
Add 3 to both sides.
2x−3 +3 <2 +3
which makes
2x<5
Divide both sides by 2.
2x/2 < 5/2
x<5/2
