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likoan [24]
3 years ago
13

Determine the solution for the equation, 5w - 9= 44.

Mathematics
2 answers:
blsea [12.9K]3 years ago
8 0

Answer:

w has multiple forms

exact w = 53/5

decimal w = 10.6

mixed number w = 10 3/5

5 x 53/5 - 9 = 44

musickatia [10]3 years ago
5 0

Answer:

w=2

Step-by-step explanation:

Simplifying

4w + -9(6 + -5w) = 44

4w + (6 * -9 + -5w * -9) = 44

4w + (-54 + 45w) = 44

Reorder the terms:

-54 + 4w + 45w = 44

Combine like terms: 4w + 45w = 49w

-54 + 49w = 44

Solving

-54 + 49w = 44

Solving for variable 'w'.

Move all terms containing w to the left, all other terms to the right.

Add '54' to each side of the equation.

-54 + 54 + 49w = 44 + 54

Combine like terms: -54 + 54 = 0

0 + 49w = 44 + 54

49w = 44 + 54

Combine like terms: 44 + 54 = 98

49w = 98

Divide each side by '49'.

w = 2

Simplifying

w = 2

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You transformed the function as follows:

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Find the value of 7v-6 given that -8v-9=7 Simplify your answer as much as possible 7v-6=
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Answer:

-20

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-8v-9=7

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-8v-9+9=7+9

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7v -6

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Mikes grandma opened a savings account in mikes name. And deposited. Some money into the account the account pays on annual simp
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Please help!! What Find the Error and explain why it is wrong!
Nata [24]

Answer:

First image attached

The error was done in Step E, because student did not multiply 2\cdot x -8 by the negative sign in numerator. Step E must be \frac{2\cdot x -5}{(x+4)\cdot (x-4)}.

Second image attached

The error was done in Step C, because the student omitted the 2\cdot a \cdot b of the algebraic identity (a+b)^{2} = a^{2}+2\cdot a\cdot b +b^{2}. Step C must be 5\cdot x = x^{2}+4\cdot x + 4

Step-by-step explanation:

First image attached

The error was done in Step E, because student did not multiply 2\cdot x -8 by the negative sign in numerator. The real numerator in Step E should be:

3-(2\cdot x -8)= 3-2\cdot x+8 = 11-2\cdot x

Hence, Step E must be \frac{2\cdot x -5}{(x+4)\cdot (x-4)}.

Second image attached

The error was done in Step C, because the student omitted the 2\cdot a \cdot b of the algebraic identity (a+b)^{2} = a^{2}+2\cdot a\cdot b +b^{2}. Step C must be 5\cdot x = x^{2}+4\cdot x + 4

And further steps are described below:

Step D

x^{2}-x+4 = 0

Which according to the Quadratic Formula, represents a polynomial with complex roots. That is: (a = 1, b = -1, c = 4)

D = b^{2}-4\cdot a\cdot c

D = (-1)-4\cdot (1)\cdot (4)

D = -17 (Conjugated complex roots)

Step E

(x-0.5-i\,1.936)\cdot (x-0.5+i\,1.936) = 0

Step F

x = 0.5+i\,1.936\,\lor\,x = 0.5-i\,1.936

8 0
3 years ago
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