(04.01)

4400 dollars is placed in an account with an annual interest rate of 7.5%. To the nearest tenth of a year, how long will it take

Katarina [22]

Answer:

Step-by-step explanation:

The equation for the amount of money in an account after a certain amount is deposited and compounded after t years once per year is

$A(t)=P(1+r)^t$

Our A(t) = 33800, P = 4400, r = .075 and we are looking for t. Filling in:

$33800=4400(1+.075)^t$ and

$33800=4400(1.075)^t$

Begin by dividing both sides by 4400 to get

$7.681818182=1.075^t$

The only way to move that t our from its current position as an exponent is to take the natural log of both sides and follow the rules for natural logs:

$ln(7.6181818182=ln(1.075)^t$

The power rule of natural logs says we can move that exponent down in front, giving us:

$ln(7.681818182)=t*ln(1.075)$

Divide both sides by ln(1.075) to get

$\frac{ln(7.61818182)}{ln(1.075)} =t$

Do this division on your calculator to get

t = 28.2 years

6 0

3 years ago

Read 2 more answers

An airplane leaves an airport at 9:00 p.M. With a heading of 270 and a speed of 610 mph. At 10:00 p.M. The pilot changes the he

timama [110]

Answer:

2330.51 miles

Step-by-step explanation:

Given that the speed of the airplane = 610 mph.

The airplane leaves an airport at 9:00 P.M. with a heading of 270 degrees and at 10:00 P.M., the pilot changes the heading to 310 degrees.

So, for 1 hour the plane is heading at 270 degrees and for 3 hours, from 10:00 p.m to 1:00 a.m, the plane is heading at 310 degrees as shown in the figure.

As, distance = time x speed, so

The distance covered at 270 degrees, $d_1 = 1\times610=610$ miles.

The distance covered at 310 degrees, $d_2 = 3\times610=1830$ miles.

Total distance covered, d, is the magnitude of the sum of vectors $\vec{d_1}$ and $\vec{d_2}$ as shown in the figure.

The angle between the vectors $\vec{d_1}$ and $\vec{d_2}$ , $\theta=310-270=40$ degree.

Magnitude of sum of the vectors \vec{d_1} and \vec{d_2},

$d= \sqrt{|\vec{d_1}|^2+|\vec{d_2}|^2+2|\vec{d_1}|\;|\vec{d_2}|\cos\theta} \\\\\Rightarrow d=\sqrt{610^2+1830^2+2|\vec{d_1}|\;|\vec{d_2}|\cos\(40^{\circ})}$

$\Rightarrow d=2330.51$ miles

Hence, at 1:00 a.m, the airplane is at a distance of 2330.51 miles from the airport.

4 0

3 years ago

im not sure on how to do this If one angle of a triangle is 30° more than twice another angle, and the third angle is equal to t

deff fn [24]

Answer:

Step-by-step explanation: How do you find the 3rd angle of a triangle?

Image result for im not sure on how to do this If one angle of a triangle is 30° more than twice another angle, and the third angle is equal to the sum of the first two angles, find the measure of each angle.

The three angles of any triangle add up to 180 degrees. Since you know two angles (35 and 40), add them together, then subtract the total from 180 to determine the degree of the third angle.

4 0

3 years ago

Write an equation for the polynomial graphed below

Anit [1.1K]

The expression for the polynomial graphed will be y(x) = (x + 3)(x - 1 )(x - 4 ).

<h3>How to factor the polynomial?</h3>

From the graph, the zeros of the polynomial of given graph are:

x = -3

x = 1

x = 4

Equate the above equations to zero

x + 3 = 0

x - 1 = 0

x - 4 = 0

Multiply the equations

(x + 3)(x - 1 )(x - 4 ) = 0

Express as a function gives;

y = (x + 3)(x - 1 )(x - 4 )

Hence, the factored form of the polynomial will be y = (x + 3)(x - 1 )(x - 4 ) .