Ask question

Ask question

All categories

3 years ago

12

Vicente se gasta 20 euros en un pantalón y una camisa. No sabe el precio de cada prenda, pero sí sabe que la camisa vale dos qui

ntas partes de lo que vale el pantalón. ¿Cuánto vale el pantalón?

1 answer:

Vlad1618 [11]3 years ago

8 0

Answer:

14.3€

Step-by-step explanation:

Let:

$C=Price\hspace{3}of\hspace{3}the\hspace{3}shirt\\P=Price\hspace{3}of\hspace{3}the\hspace{3}pants\\T=Total\hspace{3}cost$

Now, let's write the data provided by the problem, using algebraic notation.

The total cost of the clothes is 20€, so:

$P+C=T\\\\P+C=20$

The price of the shirt is :

$C=\frac{2}{5} P$

Replacing this value into the first equation:

$P+\frac{2}{5} P=20$

Solving for P:

$\frac{7}{5} P=20\\\\P=\frac{100}{7} \approx 14.3$

So, the price of the pants is 14.3€ and the price of the shirt is:

$C+14.3=20\\\\C=20-14.3=5.7$

Translation:

Deja que:

$C=Precio\hspace{3}de\hspace{3}la\hspace{3}camisa\\P=Precio\hspace{3}del\hspace{3}pantalon\\T=Costo\hspace{3}total$

Ahora, escribamos los datos proporcionados por el problema, usando notación algebraica.

El costo total de la ropa es de 20 €, entonces:

$P+C=T\\\\P+C=20$

El precio de la camisa es:

$C=\frac{2}{5} P$

Reemplazando este valor en la primera ecuación:

$P+\frac{2}{5} P=20$

Resolviendo para P:

$\frac{7}{5} P=20\\\\P=\frac{100}{7} \approx 14.3$

Entonces, el precio del pantalón es de 14.3 € y el precio de la camisa es:

$C+14.3=20\\\\C=20-14.3=5.7$

You might be interested in

I need help prove that the quadrilaterals are a parallelogram

Vlad1618 [11]

Answer:

The only shape you can make is a parallelogram. If both pairs of opposite angles of a quadrilateral are congruent, then it's a parallelogram (converse of a property). If the diagonals of a quadrilateral bisect each other, then it's a parallelogram (converse of a property).

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

Find the slope of the line. Write in simplest form<br> Show your work

Marina86 [1]

Answer:

The slope is -2.

Step-by-step explanation:

Following the line starting at the x intercept, move down 2 over right 1.

6 0

3 years ago

A paper air plane looking polygon with sides of 5 5 and 8 what is the area

VARVARA [1.3K]

If it has 3 sides then it's a triangle.
Using the formula $A= \sqrt{s(s-a)(s-b)(s-c)}$
where $s= \frac{a+b+c}{2}$
and a=5 b=5 c=8

∴ $s= \frac{5+5+8}{2} =9$
$area= \sqrt{9(9-5)(9-5)(9-8)}$
$area= \sqrt{144} = 12units^{2}$

8 0

3 years ago

What is 21000 rounded to the nearest ten thousand

denpristay [2]

A number rounded to the nearest 10000, means that the last four digits of that number (on the left of the decimal point) are 0.
<span>However, if the fourth-last digit to the left of the decimal point is 5 or greater, the number to the left of that is rounded to 1 number higher. For example, if you were rounding 145293 to the nearest 10000, it would be 150000.

However, the </span>fourth-last digit to the left of the decimal point in this case is 1.
Therefore, <span> 21000 rounded to the nearest 10000 is 20000.

</span>

4 0

3 years ago

Read 2 more answers

Help? I can't seem to understand arithmegic sequence.

katrin2010 [14]

A sequence $\{a_n\}$ is arithmetic if the difference between consecutive terms is some fixed number, regardless of which pair of consecutive terms you pick out of the sequence.

For example, the following sequences are arithmetic:

1, 2, 3, 4, 5, 6, ... (difference = 1)

-25, -20, -15, -10, -5, ... (difference = 5)

2. Carla's sequence is not arithmetic, because the differences between consecutive terms are all different:

13 - 11 = 2

17 - 13 = 4

25 - 17 = 8

She can adjust the sequence by changing the last two numbers to 15 and 17, since this makes the difference fixed:

13 - 11 = 2

15 - 13 = 2

17 - 15 = 2

and so on.

3. The sequence

45, 48, 51, 54, ...

is arithmetic with difference 3 between terms. Recursively, we can write the $n$ th term, $a_n$ , in terms of the previous, $(n-1)$ th term, $a_{n-1}$ :

$a_n=a_{n-1}+3$

By this definition, we can just as easily write the $(n-1)$ th term in terms of the $(n-2)$ th term:

$a_{n-1}=a_{n-2}+3$

Then, substituting this into the previous equation, we have

$a_n=(a_{n-2}+3)+3=a_{n-2}+2\cdot3$

We can continue this process to write $a_n$ in terms of $a_1$ :

$a_{n-2}=a_{n-3}+3\implies a_n=a_{n-3}+3\cdot3$

$a_{n-3}=a_{n-4}+3\implies a_n=a_{n-4}+4\cdot3$

and so on. (You might notice that the subscript of the term on the right side, and the number of 3s being added, together sum to $n$ .) The pattern continues down to

$a_n=a_1+(n-1)\cdot3$

The first term in this sequence is $a_1=45$ , so we have

a. $a_n=45+3(n-1)=42+3n$

where $n=1,2,3,\ldots$ .

b. You can fill in the blanks by just adding 3 to the previous term:

45, 48, 51, 54, <u>57</u>, 60, <u>63</u>, 66, 69, ...

Then, using the formula found in (a), the 15th term of the sequence is

$a_{15}=42+3\cdot15=87$

4 0

3 years ago