Hi there
To solve this question
0.03x+0.05 (6000-x)=220
Solve for x to know How much money was invested at 3%
First multiply the values
0.03x+0.05×6000-0.05x=220
0.03x+300-0.05x=220
Second calculate the difference and rearranging the values
0.03x-0.05x=220-300
-0.02x=-80
Divide both sides by-0.02 and divide the values
X=-0.02/-80
x=4000 invested at 3% this is the answer of your question
While the amount invested at 5% is
6000-4000=2000
Good luck!
We know that
points are
x intercept
A (4,0)
y intercept
B (0,11)
step 1
find the equation of a line
m=(y2-y1)/(x2-x1)--------> m=(11-0)/(0-4)------> m=-11/4
with m and the point B (0,11)
y-y1=m*(x-x1)y-11=(-11/4)*(x-0)---------> y=-(11/4)x+11
the answer is
the formula of the function is y=-(11/4)x+11
see the attached figure
Answer: If the team has one 3 out of 4 of their games, the ratio is 3/4, or 75%
Step-by-step explanation:
Answer:
This question requires a comparison between two different variables 6% and 16% values. If we let x=$ loaned on 6% loans and y=$ loaned on 16% loans, then we can relate two equations.
0.06x + 0.16y = $1500 --> referencing the interest earned from each percentage loaned.
x + y = $16000 --> referencing the total amount of money loaned out.
Rearrange either equation and substitute for a value in the other equation or use elimination to determine each individual variable.
Step-by-step explanation: