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Eva8 [605]
3 years ago
9

Write the standard form of 2 (4x - 1)(2x + 5)

Mathematics
1 answer:
kobusy [5.1K]3 years ago
7 0

Answer:

16x^2+36x-10

Step-by-step explanation:

  2 (4x - 1)(2x + 5)

=2(8x^2-2x+20x-5)

=2(8x^2+18x-5)

=16x^2+36x-10

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Answer:

x=-3

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Which inequality is graphed on the number line shown? A. x < –7 B. x > –7 C. x ≤ –7 D. x ≥ –7
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We need to see the number line before we can help you.. I'm sorry.
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GIven the function f(x) = 3x +1: (A) Find the inverse of f^-1(x). (B) Find f^-1(6)
Pani-rosa [81]

The inverse function is equal to f-1(x) = (x - 1)/3 and the value at f-1(6) is equal to 5/3.

To find the inverse, you need to switch the f(x) and x in the equation. Then you can solve for the new f(x). The result will be the inverse (f-1)

f(x) = 3x + 1 ----> Switch f(x) and x

x = 3f(x) + 1 ----> Subtract 1

x - 1 = 3f(x) ----> Divide by 3.

f-1(x) = (x - 1)/3

Now that we have the inverse, we can plug 6 in to get the value at f-1(6).

f-1(x) = (x - 1)/3

f-1(6) = (6 - 1)/3

f-1(6) = 5/3

3 0
3 years ago
Find the recursive quadratic formula of the sequence: 1, 3, 7, 13, 21
Anika [276]

The sequence

1, 3, 7, 13, 21, ...

has first-order differences

2, 4, 6, 8, ...

Let a_n denote the original sequence, and b_n the sequence of first-order differences. It's quite clear that

b_n=2n

for n\ge1. By definition of first-order differences, we have

b_n=a_{n+1}-a_n

for n\ge1, or

a_{n+1}=a_n+2n

By substitution, we have

a_n=a_{n-1}+2(n-1)

\implies a_{n+1}=(a_{n-1}+2(n-1))+2n

\implies a_{n+1}=a_{n-1}+2(n+(n-1))

a_{n-1}=a_{n-2}+2(n-2)

\implies a_{n+1}=(a_{n-2}+2(n-2))+2(n+(n-1))

\implies a_{n+1}=a_{n-2}+2(n+(n-1)+(n-2))

and so on, down to

a_{n+1}=a_1+2(n+(n-1)+\cdots+2+1)

You should know that

1+2+\cdots+(n-1)+n=\dfrac{n(n+1)}2

and we're given a_1=1, so

a_{n+1}=1+n(n+1)=n^2+n+1

or

a_n=(n-1)^2+(n-1)+1\implies\boxed{a_n=n^2-n+1}

Alternatively, since we already know the sequence is supposed to be quadratic, we can look for coefficients a,b,c such that

a_n=an^2+bn+c

We have

a_1=a+b+c=1

a_2=4a+2b+c=3

a_3=9a+3b+c=7

and we can solve this system for the 3 unknowns to find a=1,b=-1,c=1.

4 0
4 years ago
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