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Eva8 [605]
3 years ago
9

Write the standard form of 2 (4x - 1)(2x + 5)

Mathematics
1 answer:
kobusy [5.1K]3 years ago
7 0

Answer:

16x^2+36x-10

Step-by-step explanation:

  2 (4x - 1)(2x + 5)

=2(8x^2-2x+20x-5)

=2(8x^2+18x-5)

=16x^2+36x-10

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If the initial amount of iodine-131 is 537 grams , how much is left after 10 days?
viktelen [127]

Answer:

225.78 grams

Step-by-step explanation:

To solve this question, we would be using the formula

P(t) = Po × 2^t/n

Where P(t) = Remaining amount after r hours

Po = Initial amount

t = Time

In the question,

Where P(t) = Remaining amount after r hours = unknown

Po = Initial amount = 537

t = Time = 10 days

P(t) = 537 × 2^(10/)

P(t) = 225.78 grams

Therefore, the amount of iodine-131 left after 10 days = 225.78 grams

4 0
3 years ago
How do you put mixed fractions on a number line in decimal form?
Natalka [10]
Like you would put 0.5 or 1. or 1.5 as like 1/2 or 1/3  and you plot negatives first
5 0
3 years ago
2x²-5x-12=0 (simplify solution set)
Arada [10]

Answer:

x = 4 or x = -3/2

Step-by-step explanation:

To simplify and solve this, let's use the quadratic formula.

So the format of a quadratic equation is supposed look like this:

ax^2+bx+c=0

Let's find a, b, c:

  • a is the coefficient of x^2
  • b is the coefficient of x
  • c is the constant term

Now let's solve the equation.

Let's solve your equation step-by-step.

2x^2−5x−12=0

For this equation: a=2, b=-5, c=-12

2x^2+−5x+−12=0

Step 1: Use quadratic formula with a=2, b=-5, c=-12.

x=\frac{-b\pm\sqrt{b^2-4ac} }{2a}

x=\frac{-(-5)\pm\sqrt{(-5)^2-4(2)(-12)} }{2(2)}

x=\frac{5\pm\sqrt{121} }{4}

x=4 or x=\frac{-3}{2}

<u />

<u>Answer:</u>

x = 4 or x = -3/2

7 0
2 years ago
1. What is an equivalent expression for
ipn [44]

Answer:

i am so confused right now :)::):::)::):))

Step-by-step explanation:

5 0
3 years ago
ASAP!! ILL GIVE BRAINLEST
Alex
I think A^3:B^

Explanation:

It is 3 dimensional, so the surface area would be 3x bigger, so A^3:B^
5 0
3 years ago
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