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Xelga [282]
3 years ago
12

The average price of gas in 2000 was $1.57 per gallon, and $2.30 in 2005. What is the rate of change for each year between 2000

to 2005?
Mathematics
1 answer:
KATRIN_1 [288]3 years ago
8 0

Answer: $ 0.146 per year.

Step-by-step explanation:

Given: Average price of gas in 2000 = $1.57 per gallon

Average price of gas in 2005 = $2.30 per gallon

The rate of change for each year between 2000 to 2005

= \dfrac{\text{Change in price}}{\text{Change in time}}

=\dfrac{\text{Price in 2005- Price in 2000}}{2005-2000}\\\\=\dfrac{2.30-1.57}{5}\\\\=\dfrac{0.73}{5}=0.146

Hence, the rate of change for each year between 2000 to 2005 is $ 0.146 per year.

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Neporo4naja [7]

Answer:

V=61.66

Step-by-step explanation:

This problem can be solved by using the expression for the Volume of a solid with the washer method

V=\pi \int \limit_a^b[R(x)^2-r(x)^2]dx

where R and r are the functions f and g respectively (f for the upper bound of the region and r for the lower bound).

Before we have to compute the limits of the integral. We can do that by taking f=g, that is

f(x)=g(x)\\ln(x)=\frac{1}{2}x-2

there are two point of intersection (that have been calculated with a software program as Wolfram alpha, because there is no way to solve analiticaly)

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and because the revolution is around y=-5 we have

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V=\pi \int \limit_{x1}^{x2}[(lnx+5)^2-(\frac{1}{2}x+3)^2]dx\\

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Hope this helps

regards

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3 years ago
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Answer:

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Step-by-step explanation:

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Find the measures of the angles of a triangle whose angles have a measure of x, 1/2x, and 1/6x. Also, what kind of triangle is i
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the sum of the angles in a triangle = 180°, thus

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10x = 1080 ( divide both sides by 10 )

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Since all the angles are different and the largest is 108°

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