The intersections of the equations represent the times when the bird and the ball are at the same height.
8t+20=-16t^2+65t
16t^2-57t+20=0, using the quadratic equation for expediency:
t=(57±√4529)/32 and since we know t>0
t≈3.88 seconds (at a approximate height of 51 feet)
Multiply 198 by 3 or 4 and find he closest one
Multiply 5 with y equals 5y the divide 30 by 5 and multiply your answers
I think it would be B but I’m not sure for number 7
