$Hence\ HI=IJ\\\\y^2-10=4y+2\\\\y^2-4y-12=0\\\\y^2-6y+2y-12=0\\\\y(y-6)+2(y-6)=0\\\\(y-6)(y+2)\\\\y\ can\ not\ be\ negative\ as\ in\ that\ case\ IJ\ will\ be\ negative.\\\\Hence\ y=6\\\\IJ=4y+2=4\times 6+2=26\\\\\\\\Tangents\ at\ J\ and\ L\ meet\ at\ K.\ Use\ two\ tangent\ theorem.\\\\JK=KL\\\\5x+1=6x-3\\\\6x-5x=1+3\\\\x=4\\\\JK=5x+1=5\times 4+1=21\\\\\\IK=IJ+JK=26+21\\\\IK=47$

6 0

3 years ago

Which term describes the dotted line in the quadrilateral?

Tasya [4]

The correct answer is C diagonal

7 0

3 years ago

4) Use the distance formula to find the length of segment BC.

gogolik [260]

Answer:

Step-by-step explanation:

d= √(5-1)^2+(1-4)^2

d= √4^2+(-3)^2

d= √16+9

d=√25

d=5

8 0

3 years ago