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marissa [1.9K]
2 years ago
6

25k + 12 = -13 Help me plsss

Mathematics
2 answers:
stira [4]2 years ago
7 0
The answer is k=-1.........
wel2 years ago
4 0

Answer:

k=-1

Step-by-step explanation:

25k= -13-12

k= -25÷25

k=-1

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Find mZECD<br> E<br> D<br> C С<br> 31°<br> A<br> B<br> PLEASE HELP I WILL GIVE BRAINLIEST
Nadya [2.5K]
Angle ECD is 118°, let me know if you need an explanation or just wanted the answer
7 0
2 years ago
A. 76°<br><br> B. 72°<br><br> C. 70°<br><br> D. 12°
Crank

Answer:measurement of angle B is

70 \:  \: degrees

<h3>Answer C is correct</h3>

Step-by-step explanation:

6x - 2 + 5x + 18 + 2x + 8 = 180 \\ 13x + 24 = 180 \\ 13x = 180 - 24 \\ 13x = 156 \\  \frac{13x}{13}  =  \frac{156}{13}  \\ x = 12 \:  \: degrees

7 0
3 years ago
20 points SEND HELP SMART PEEPS IF YOU KNOW THE ANSWER PLEASE HELP
4vir4ik [10]

Answer:

19

Step-by-step explanation:

on edge 2020

4 0
3 years ago
Read 2 more answers
Solve using Fourier series.
Olin [163]
With 2L=\pi, the Fourier series expansion of f(x) is

\displaystyle f(x)\sim\frac{a_0}2+\sum_{n\ge1}a_n\cos\dfrac{n\pi x}L+\sum_{n\ge1}b_n\sin\dfrac{n\pi x}L
\displaystyle f(x)\sim\frac{a_0}2+\sum_{n\ge1}a_n\cos2nx+\sum_{n\ge1}b_n\sin2nx

where the coefficients are obtained by computing

\displaystyle a_0=\frac1L\int_0^{2L}f(x)\,\mathrm dx
\displaystyle a_0=\frac2\pi\int_0^\pi f(x)\,\mathrm dx

\displaystyle a_n=\frac1L\int_0^{2L}f(x)\cos\dfrac{n\pi x}L\,\mathrm dx
\displaystyle a_n=\frac2\pi\int_0^\pi f(x)\cos2nx\,\mathrm dx

\displaystyle b_n=\frac1L\int_0^{2L}f(x)\sin\dfrac{n\pi x}L\,\mathrm dx
\displaystyle b_n=\frac2\pi\int_0^\pi f(x)\sin2nx\,\mathrm dx

You should end up with

a_0=0
a_n=0
(both due to the fact that f(x) is odd)
b_n=\dfrac1{3n}\left(2-\cos\dfrac{2n\pi}3-\cos\dfrac{4n\pi}3\right)

Now the problem is that this expansion does not match the given one. As a matter of fact, since f(x) is odd, there is no cosine series. So I'm starting to think this question is missing some initial details.

One possibility is that you're actually supposed to use the even extension of f(x), which is to say we're actually considering the function

\varphi(x)=\begin{cases}\frac\pi3&\text{for }|x|\le\frac\pi3\\0&\text{for }\frac\pi3

and enforcing a period of 2L=2\pi. Now, you should find that

\varphi(x)\sim\dfrac2{\sqrt3}\left(\cos x-\dfrac{\cos5x}5+\dfrac{\cos7x}7-\dfrac{\cos11x}{11}+\cdots\right)

The value of the sum can then be verified by choosing x=0, which gives

\varphi(0)=\dfrac\pi3=\dfrac2{\sqrt3}\left(1-\dfrac15+\dfrac17-\dfrac1{11}+\cdots\right)
\implies\dfrac\pi{2\sqrt3}=1-\dfrac15+\dfrac17-\dfrac1{11}+\cdots

as required.
5 0
2 years ago
Determine the range of the following graph:
BaLLatris [955]

Answer:

The range of a function is the set of outputs the function can give

The y-axis on the graph shows as the output of the function

From the graph, we can see that the outputs of this specific function range from 0 to 5

Therefore, the range of this function is:   [0 , 5]

3 0
3 years ago
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