How many ways are there to choose positive integers a, b and c, not necessarily distinct, so that a + b < c and c ≤ 5?
1 answer:
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Answer:
(0,0)
Step-by-step explanation:
We have,
U = { (x,y) : x,y belong to real numbers }
A = { (x,y) : (x,y) is a solution of y=x }
B = { (x,y) : (x,y) is a solution of y=2x }
We need to find the ordered pair (x,y) that belong to AB.
Let, (x,y) belong to AB
i.e. (x,y) belong to A and (x,y) belong to B
i.e. y = x and y = 2x
i.e. x = 2x
i.e. x = 0
Now, substitute x= 0 in any of the equation say y = x, we get y = 0.
Hence, the ordered pair satisfying AB is (0,0).