Answer:
Step-by-step explanation:
We are given a circle with a partially shaded region. First, we need to determine the area of the whole circle. To do this, we need the measurement of the radius of the circle:
Use the Pythagorean theorem to solve for the other leg of the right triangle inside the circle:
5^2 = 3^2 + x^2
x = 4
The radius is 4 + 1 cm = 5 cm
So the area of the circle is A = pi*r^2
A = 3.14 * (5)^2
A = 25pi cm^2
To solve for the area of the shaded region:
Ashaded = Acircle - Atriangles
we need to solve for the area of the triangles:
A = 1/2 *b*h
A = 1/2 *6 * 5
A = 15 cm^2
Atriangles = 2 * 15
Atriangles = 30 cm^2
Ashaded = 25pi - 30
1 day = 24 hours
1 hour = 60 minutes
1 minute = 60 seconds
60 seconds x 60 minutes = 3,600 seconds per hour
3,600 seconds per hour x 24 hours = 86,400 seconds per day.
The light flashes 5 times every 10 seconds:
5 flashes / 10 seconds = 1 flash every 2 seconds
86,400 seconds / 2 seconds = 43,200 flashes per day.
Answer:
y=-37
Step-by-step explanation:
0+6y=7(y+6)-5
0+6y=7y+42-5
6y=7y+37
-1y=37
y=-37
(y2-y1)/(x2-x1)=
slope: 21/26
Answer:
Step-by-step explanation:
The question is asking you to graph the equations.
The equations are in slope intercept form so y=mx+b
M is the slope and b is the y-intercept
First draw the y & x axis and label/number them
The y-intercept for the first equation is -1 so draw a dot on the -1 on the y-axis
The slope is 2/5 and you use rise/run to continue the slope.
you rise 2 on the y-axis and go right 5 times on the x-axis (for a negative number you go left/down)
For the second equation, you have to turn it into slope intercept form.
You should get y=2/3x+3
You graph this equation the same as you did the first one.
