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2 years ago

Last week, 4/5 of the students in Mr. Zanker's class went on a field trip. 9/10 of

Mathematics

1 answer:

Basile [38]2 years ago

7 0

Answer:

The average of students in the two classes who went on the field trip is $\frac{17}{20}$ .

Step-by-step explanation:

Average = $\frac{sum \: \: of \: \:observations }{no. \: \: of \: \:observations}$

Average of students in the two classes =

$\frac{ \frac{4}{5} + \frac{9}{10} }{2}$

$\frac{ \frac{8+9 }{ 10} }{2}$

$\frac{ \frac{17}{10} }{2}$

$\frac{17}{20}$

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4x+1=9+4y solve for y

koban [17]

Answer:

y = x-2

Step-by-step explanation:

6 0

3 years ago

Round your answer to the nearest whole dollar

sleet_krkn [62]

A.

First you have to evaluate (2000* .045) then you take that and multiply by 8 then you add the answer to 2000.

so 2720 is your answer.

5 0

2 years ago

Does it matter which dimensions you select for the lenght and the width when you find the area of a rectangle? Explain

Levart [38]

It does not. So Long as the length is multipled by the height aka Long edge multiplied with the short edge, you will obtain the area of the rectangle.

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3 years ago

Suppose a company did $2,000,000 in annual maintenance in 2013 and expects 80% of those to renew for 2014. Suppose that product

Paha777 [63]

Answer:

$1,750,000

Step-by-step explanation:

The company did $2,000,000 in annual maintenance in 2013 and expects 80% of those to renew for 2014.

That will result in annual maintenance of:

(80 / 100) * 2000000 = $1,600,000

The product sales for 2013 were 2,000,000 (which include free maintenance in 2013) and 75% of those were expected to pay annual maintenance of 10% of the purchase price in 2014.

That will result in annual maintenance of:

(75 / 100) * (10 / 100) * 2000000 = $150,000

Therefore, the total annual maintenance will be:

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6 0

2 years ago

In the exercise, X is a binomial variable with n = 5 and p = 0.2. Compute the given probability. Check your answer using technol

Ronch [10]

Answer:

0.0512

Step-by-step explanation:

We are told in the question that X isa Binomial variable. Hence we solve this question, using the formula for Binomial probability.

The formula for Binomial Probability = P(x) = (n!/(n - x) x!) × p^x × q ^n - x

In the above question,

x = 3

n = 5

p = probability for success = 0.2

q = probability for failures = 1 - 0.2 = 0.8

P(x) = (n!/(n - x) x!) × p^x × q ^n - x

P(3) = (5!/(5 - 3) 3!) × 0.2^3 × 0.8^5-3

P(3) =( 5!/2! × 3!) × 0.2³ × 0.8²

P(3) = 10 × 0.008 × 0.64

P(3) = 0.0512

6 0

3 years ago