The probability that at least two of the missiles hit the arsenal:
P ( x ≥ 2 ) = P ( x = 2 ) + P ( x = 3 )
P ( x = 2 ) = 0.75 · 0.85 · 0.1 + 0.85 · 0.9 · 0.25 + 0.75 · 0.9 · 0.15 =
= 0.06375 + 0.10125 + 0.19125 = 0.35625
P ( x = 3 ) = 0.75 · 0.85 · 0.9 = 0.57375
P ( x ≥ 2 ) = 0.35625 + 0.57375 = 0.93
Answer:
The probability is 0.93 or 93%.
Answer: RQ= 8.99 ( approx)
Step-by-step explanation:
Let MR= x
Since, In triangle, PRQ, tan 75°= 
⇒ RQ= 
Now, In triangle MRQ,
tan 60°= 
⇒ RQ= 
On equating both values of RQ,

⇒
⇒
⇒
⇒
⇒
≈15.60
Thus RQ=8.99999999999≈8.99
Answer:
THE CORRECT IS B(a and b)= p(A).P(B)