Step-by-step explanation:
We want to find two things-- the speed of the boat in still water and the speed of the current. Each of these things will be represented by a different variable:
B = speed of the boat in still water
C = speed of the current
Since we have two variables, we will need to find a system of two equations to solve.
How do we find the two equations we need?
Rate problems are based on the relationship Distance = (Rate)(Time).
Fill in the chart with your data (chart attached)
The resulting speed of the boat (traveling upstream) is B-C miles per hour. On the other hand, if the boat is traveling downstream, the current will be pushing the boat faster, and the boat's speed will increase by C miles per hour. The resulting speed of the boat (traveling downstream) is B+C miles per hour. Put this info in the second column in the chart. Now plug it into a formula! <u>Distance=(Rate)(Time) </u>Now solve using the systems of equations!
The first fraction is 4 over 6, right? hopefully it is, i cant really see.
Basically, you can divide 4 and 6 by the same number, they have factors in common. They're both multiples of 2. if you divide them both by 2, you get 2 over 3, which is the <em>exact same amount as 4 over 6, it's just written in a simpler way. </em>the first answer is 2 over 3.
What numbers can both 10 and 15 be divided by? give it a try.
They can help you find a common denominator by the bottoms of each fraction if the top ones don't have the same denominator.
Idk what you mean the answer is 15 students eat six pizzas